Light refraction from water at 23.0° to vertical

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kaptinmorgan
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Homework Statement



A diver shines a flashlight upward from beneath the water at a 23.0° angle to the vertical. At what angle does the light leave the water?

Homework Equations


I thought that i could use snell's law here...but i don't know what to do afterwards...



The Attempt at a Solution



angle of incidence is 23... and the index of refraction is 1.333

1.333 (sin 23) = 1 (sin x)

is that about right?
 
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kaptinmorgan said:
angle of incidence is 23... and the index of refraction is 1.333

1.333 (sin 23) = 1 (sin x)

is that about right?

Write very clearly what x represents here. What do you feel that the question wants?