How Do You Calculate Light Refraction Angles Through Quartz?

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SUMMARY

The discussion focuses on calculating light refraction angles through a 2.00 cm thick block of fused quartz with a refractive index (n) of 1.458. The user applied Snell's Law, stating that n1*sin(θ1) = n2*sin(θ2), to find the angles of incidence and refraction. However, they encountered an error with their TI-89 calculator, which produced an incorrect output. The solution involves ensuring the calculator is set to degree mode to accurately compute the angles as light enters and exits the quartz.

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  • Understanding of Snell's Law and its application in optics
  • Familiarity with the concept of refractive index
  • Basic knowledge of light behavior at interfaces
  • Experience using a TI-89 calculator for trigonometric calculations
NEXT STEPS
  • Research the application of Snell's Law in different materials
  • Learn how to set and verify calculator modes, specifically on the TI-89
  • Explore the properties of fused quartz and its optical characteristics
  • Study the principles of light reflection and refraction in various mediums
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Students and professionals in physics, optics researchers, and anyone interested in the practical applications of light refraction principles.

myersb05
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(SOLVED) Calculator Entry ErrorAngles of Reflection of Light

A ray of light strikes a flat 2.00 cm thick block of fused quartz (n = 1.458) at an angle of θ = 27.0° with the normal (Fig. P22.18). Trace the light beam through the fused quartz and find the angles of incidence and refraction at each surface.



Snell's Law=n1sintheta1=n2sintheta2



Since the ray of light began in air, I used 1*sin(27)=1.458*sin(x) and solved but my TI-89 gave me 360*@n6+.449605 which makes no sense to me. Could I get some guidance please?
I have to find the angles as it enters and leaves the quartz
 
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is your calculator in degree mode?
 

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