- #1

- 4

- 0

lim( 1/1.3+1/3.5+......1/(2n-1)(2n+1))

where x tends to infinty?

where x tends to infinty?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter succhi
- Start date

- #1

- 4

- 0

lim( 1/1.3+1/3.5+......1/(2n-1)(2n+1))

where x tends to infinty?

where x tends to infinty?

- #2

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 963

Write the first several terms out in that form and see what happens.

- #3

- 4

- 0

Write the first several terms out in that form and see what happens.[/

hey i have tried by this method but this not giving me the right ans could plz solve this briefly 4 me

- #4

mathman

Science Advisor

- 7,924

- 467

Write the first several terms out in that form and see what happens.

You have a sign error! Should be 1/(2n-1)(2n+1)= (1/2)/(2n-1) -(1/2)/(2n+1).

- #5

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 963

Then what did you get for, say, the first 5 terms?

Write the first several terms out in that form and see what happens.[/

hey i have tried by this method but this not giving me the right ans could plz solve this briefly 4 me

Ouch! The fact that one is positive and the other negative is what makes it all work!You have a sign error! Should be 1/(2n-1)(2n+1)= (1/2)/(2n-1) -(1/2)/(2n+1).

Share:

- Replies
- 2

- Views
- 2K