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lim( 1/1.3+1/3.5+......1/(2n-1)(2n+1))
where x tends to infinty?
where x tends to infinty?
By "partial fractions", 1/(2n-1)(2n+1)= (1/2)/(2n-1)+ (1/2)/(2n+1).
Write the first several terms out in that form and see what happens.[/
hey i have tried by this method but this not giving me the right ans could plz solve this briefly 4 me
You have a sign error! Should be 1/(2n-1)(2n+1)= (1/2)/(2n-1) -(1/2)/(2n+1).By "partial fractions", 1/(2n-1)(2n+1)= (1/2)/(2n-1)+ (1/2)/(2n+1).
Write the first several terms out in that form and see what happens.
Then what did you get for, say, the first 5 terms?By "partial fractions", 1/(2n-1)(2n+1)= (1/2)/(2n-1)+ (1/2)/(2n+1).
Write the first several terms out in that form and see what happens.[/
hey i have tried by this method but this not giving me the right ans could plz solve this briefly 4 me
Ouch! The fact that one is positive and the other negative is what makes it all work!You have a sign error! Should be 1/(2n-1)(2n+1)= (1/2)/(2n-1) -(1/2)/(2n+1).