Limit as x Approaches 5: Right = 3, Left = 8, Does Not Exist?

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Homework Help Overview

The problem involves evaluating the limit of a piecewise function as x approaches 5 from both the left and the right. The function is defined differently for values less than or equal to 5 and for values greater than 5.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the values obtained for the limit from both sides and question the correctness of their evaluations. There is an exploration of the function's behavior at the point x = 5.

Discussion Status

Some participants have acknowledged a mistake in the initial evaluations but are seeking confirmation on the corrected values. There is an indication that the discussion is ongoing, with some participants expressing uncertainty about the correctness of their findings.

Contextual Notes

There is mention of a webworks system providing feedback that suggests the evaluations may be incorrect, prompting further discussion about the limits.

OrbitalPower

Homework Statement


Says: Let f(x) = x + 3 if x \le5 and
f(x) = 3 if x > 5

And then it asks you to find the limit as x approaches 5 from the left, right, and as x = 5.

I get 3 as x approaches from the right, 8 from the left, and does not exist other words. But he says that's not correct. What am I doing wrong.
 
Last edited by a moderator:
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Sounds like you reversed the directions.
 
Yah, I did. I reversed it as a wrote it, but I fixed it. Otherwise it is correct?

When x approaches 3 from the left, I should get 8. And from the right, i should get 3. And I don't think it exists at x = 5.

This is for a friend but his webworks says that's wrong.
 
Last edited by a moderator:
Yep.
 
cool thanks. I think an email needs to be sent.
 

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