Limit as x Approaches 5: Right = 3, Left = 8, Does Not Exist?

[OrbitalPower]

Homework Statement

Says: Let $$f(x) = x + 3$$ if $$x \le5$$ and
f(x) = 3 if $$x > 5$$

And then it asks you to find the limit as x approaches 5 from the left, right, and as x = 5.

I get 3 as x approaches from the right, 8 from the left, and does not exist other words. But he says that's not correct. What am I doing wrong.

 

[Mathdope]

Sounds like you reversed the directions.

 

[OrbitalPower]

Yah, I did. I reversed it as a wrote it, but I fixed it. Otherwise it is correct?

When x approaches 3 from the left, I should get 8. And from the right, i should get 3. And I don't think it exists at x = 5.

This is for a friend but his webworks says that's wrong.

 

[Mathdope]

Yep.

 

[OrbitalPower]

cool thanks. I think an email needs to be sent.