MHB Limit Laws and Techniques: What is the difference between left and right limits?

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The difference between left and right limits is defined by the direction from which x approaches a specific value c. The notation x->c^- indicates approaching c from the negative side, while x->c^+ indicates approaching from the positive side. For instance, as x approaches 0 from the right, the limit of 1/x tends to positive infinity, while from the left, it tends to negative infinity. In piecewise functions, the left and right limits can yield different results, as shown in the example where limits at x=2 differ based on the function's definition. A limit exists at a point if both one-sided limits exist and are equal, confirming the continuity of the function at that point.
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What is the difference of x->c^- and x->c^+?
 
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[math]\lim_{x \to c^-}[/math] approaches c from the negative side of the x-axis and [math]\lim_{x \to c^+}[/math] approaches c from the positive side. For example [math]\lim_{x \to 0^+} \dfrac{1}{x} \to + \infty[/math] whereas [math]\lim_{x \to 0^-} \dfrac{1}{x} \to - \infty[/math].

-Dan
 
Or you can have a "piecewise" function like
f(x)= 3x+ 1 if x< 2 and
f(x)= 2x- 2 if x> 2

Then [math]\lim_{x\to 2^-} f(x)= \lim_{x\to 2} 3x+ 1= 3(2)+ 1= 7[/math] since we only look at x less than 2 and
[math]\lim_{x\to 2^+} f(x)= \lim_{x\to 2} 2x- 2= 2(2)- 2= 2[/math] since we only look at x greater than 2.

For a general function, g, the limit, [math]\lim_{x\to a} g(x)[/math] exists if and only if both [math]\lim_{x\to 2^-} g(x)[/math] and [math]\lim_{x\to a+} g(x)[/math] exist and are equal (and, of course, [math]\lim_{x\to a} g(x)[/math] is their common value).
 
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