MHB Limit Laws and Techniques: What is the difference between left and right limits?

  • Thread starter Thread starter Tracy18
  • Start date Start date
  • Tags Tags
    Laws Limit
Tracy18
Messages
3
Reaction score
0
What is the difference of x->c^- and x->c^+?
 
Mathematics news on Phys.org
[math]\lim_{x \to c^-}[/math] approaches c from the negative side of the x-axis and [math]\lim_{x \to c^+}[/math] approaches c from the positive side. For example [math]\lim_{x \to 0^+} \dfrac{1}{x} \to + \infty[/math] whereas [math]\lim_{x \to 0^-} \dfrac{1}{x} \to - \infty[/math].

-Dan
 
Or you can have a "piecewise" function like
f(x)= 3x+ 1 if x< 2 and
f(x)= 2x- 2 if x> 2

Then [math]\lim_{x\to 2^-} f(x)= \lim_{x\to 2} 3x+ 1= 3(2)+ 1= 7[/math] since we only look at x less than 2 and
[math]\lim_{x\to 2^+} f(x)= \lim_{x\to 2} 2x- 2= 2(2)- 2= 2[/math] since we only look at x greater than 2.

For a general function, g, the limit, [math]\lim_{x\to a} g(x)[/math] exists if and only if both [math]\lim_{x\to 2^-} g(x)[/math] and [math]\lim_{x\to a+} g(x)[/math] exist and are equal (and, of course, [math]\lim_{x\to a} g(x)[/math] is their common value).
 
Last edited:
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.

Similar threads

Back
Top