- #1

Vali

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Also, I know that x1 is the lowest root of this equation.

I need to solve lim (x1) as m->infinity

A. 1

B. 3/2

C. 0

D. -1/2

E. -1

I tried to solve the equation with the discriminant then to calculate the limit but didn't work.

Also, I think that because x1 is the lowest root and the function graphic is a parabola, I tink that -b/2a (the peak of parabola) > x1 but I don't see how this condition would help me.

Some ideas?

Thanks!