Limit of 10^n/n as n-> infinity

[ayandas]

Hi,

Can anyone please suggest a solution to the problem:

lim 10ⁿ/(n!)
n->(infinite)

 

[sjb-2812]

When n is large, the numerator is much larger than the demoninator, so the limit is 0, surely?

 

[mg0stisha]

Are you sure? When n is small, the numerator is larger, but when n gets large, the denominator is actually larger.

EDIT: Next time, put a question like this in the 'Homework Questions' section. That's where it should be, and you'll also probably get a response faster that way.

 

[sjb-2812]

My bad, got the names the wrong way round ;)

 

[mg0stisha]

No worries, just didn't want to confuse the OP!