MHB Limit of Function at x=0: Does Not Exist (DNE)

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SUMMARY

The limit of the function $$f(x)=\frac{\dfrac{1}{7x}-1}{e^{7x}-1}$$ as x approaches 0 does not exist (DNE) in the traditional sense, as it approaches infinity from both the left and right sides. Specifically, $$\lim_{x\to0^{-}}f(x)=\infty$$ and $$\lim_{x\to0^{+}}f(x)=\infty$$. However, based on the exercise's instructions, the correct response should be "I" to indicate that the limit approaches positive infinity.

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josesalazmat
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hello
I have an exercise which says:

Evaluate the following limit. Enter -I if your answer is −∞, enter I if your answer is ∞, and enter DNE if the limit does not exist.

$$ limx→0[(1/(7x)−(1)/((e^(7x))−1)] $$ e power 7x

when I follow the graph for $$1/7x$$ the limit does not exist (goes to infinite for the right and -infinite for the left)it is the same for $$1/(((e^(7x))−1)$$

my answer is DNE but it is wrong

where is a mistake?

Thanks

Jose
 
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Let:

$$f(x)=\frac{\dfrac{1}{7x}-1}{e^{7x}-1}$$

We see that:

$$\lim_{x\to0^{-}}f(x)=\lim_{x\to0^{+}}f(x)=\infty$$

Technically, this limit does not exist, but given the instructions, I would answer with "I."
 
Relativistic Momentum, Mass, and Energy Momentum and mass (...), the classic equations for conserving momentum and energy are not adequate for the analysis of high-speed collisions. (...) The momentum of a particle moving with velocity ##v## is given by $$p=\cfrac{mv}{\sqrt{1-(v^2/c^2)}}\qquad{R-10}$$ ENERGY In relativistic mechanics, as in classic mechanics, the net force on a particle is equal to the time rate of change of the momentum of the particle. Considering one-dimensional...

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