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## Homework Statement

the title says it all

[tex]x \rightarrow 4[/tex]

for [tex]f\left(x\right) = \frac{\sqrt{1+2x}-3}{\sqrt{x}-2}[/tex]

I have multiplied both top and bottom by conjugate, [tex]\sqrt{x}+2[/tex]:

[tex]f\left(x\right) = \frac{\sqrt{x(1+2x)}+2\sqrt{1+2x} -3\sqrt(x)-6}{x-4}[/tex]

but don't know how to take this further. Dividing both numerator and denominator by x doesn't help.