Limiting Reagent Calculation for Zinc and Sulfur Reaction

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Discussion Overview

The discussion revolves around a limiting reagent calculation involving a reaction between zinc and sulfur. Participants explore how to determine the amount of zinc that remains unreacted after the reaction, considering the quantities of both reactants provided in a homework problem.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Conceptual clarification

Main Points Raised

  • One participant suggests that the total mass of the reactants is 14.0 g and speculates that half of the zinc would remain unreacted.
  • Another participant clarifies that this is a limiting reagent problem and indicates that the amount of zinc that reacts can be determined based on the grams of sulfur available.
  • A participant expresses uncertainty about the law of constant composition and seeks guidance on how to find the amount of zinc that does not react.
  • There is a question about the compound formed from the reaction, with one participant proposing that it is zinc sulfide.
  • Participants discuss the correct formula for zinc sulfide, with one suggesting ZnS2 and another correcting this to ZnS based on the ionic charges of zinc and sulfur.
  • One participant calculates the moles of zinc and sulfur, concluding that 0.028 moles of zinc will remain unreacted after the reaction.
  • A later reply questions whether the same calculation would apply if the question were about the amount of sulfur remaining unchanged.
  • Another participant confirms the previous calculation and notes that all sulfur would theoretically be used up, as it is the limiting reagent.

Areas of Agreement / Disagreement

Participants generally agree on the identification of sulfur as the limiting reagent and the resulting calculation of unreacted zinc. However, there is some uncertainty regarding the correct formula for zinc sulfide and the implications of the limiting reagent concept.

Contextual Notes

Some participants express confusion about the law of constant composition and the stoichiometry of the reaction, indicating a need for further clarification on these concepts.

priscilla98
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Homework Statement


4.0 g of sulfur and 10.0 g of zinc are heated together, how much zinc will remain unreacted?

Homework Equations




The Attempt at a Solution



If these two elements are heated together, wouldn't the total mass (g) be 14.0 by adding the amount of sulfur and zinc together. I'm thinking half of the zinc would remain unreacted
 
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This is a limiting reagent problem; are you familiar with those?

The sulfur and zinc will form one compound. And since the problem already tells you that not all the zinc will react, you'll find out exactly how much will react, based off of the grams of sulfur you have.
 
Well, i just started ap chem and i have no clue about the law of constant composition. Therefore, as you say, not all of the zinc will react, but how exactly do you find out how much zinc will not react
 
Do you know what compound is made with zinc and sulfur?
 
Wouldn't it make zinc sulfide?
 
And what's the formula for zinc sulfide? Then write the complete equation for the reaction.
 
Is the formula ZnS2? I'm thinking since its sulfide then it would be bottom squared for S.
 
priscilla98 said:
Is the formula ZnS2? I'm thinking since its sulfide then it would be bottom squared for S.

Not quite, think of what the charges are for Zn and S as ions.
 
ok the charge for Zn is + 2 and the charge for S is - 2. So wouldn't the charges cross out and it would be just ZnS?
 
  • #10
Right, so the equation is Zn + S → ZnS.

Since some of the zinc remains unreacted, that means all of the sulfur will react with part of the zinc.
Now given 4.0 g S, how could we start finding out how much Zn will react with that?
 
  • #11
Ok i think I am starting to understand it.

Moles of Zn = 10 g./65.4 g/mole = 0.153 moles

Moles of S = 4g/32.1 g/mole = 0.125 moles

Per the reaction Zn and S react in a 1:1 ratio so when the 0.125 mole of S are consumed the reaction will stop and 0.153-0.125 = 0.028 moles of Zn will remain.

0.028 mole(65.4g/mole) = 1.82 grams of Zn remain

But would it be the same answer if they ask how much sulfur will remain unchanged?
 
  • #12
You got the answer, good job. :smile:

Asking how much sulfur will remain unchanged wouldn't make sense since all of it (theoretically) would be used up because it is the limiting reagent and there is excess zinc.
 

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