ozkan12
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if $\lim_{{n}\to{\infty}} {y}_{m+1}={x}^{*}$, Can we say that $\lim_{{n}\to{\infty}} {y}_{n-1}={x}^{*}$...Please pay attention, I say m and n...
The discussion centers on the limits of sequences as they approach infinity, specifically addressing the relationship between two independent sequences, \(y_m\) and \(y_n\). It is established that if \(\lim_{m\to\infty} y_{m+1} = x^*\), then it follows that \(\lim_{n\to\infty} y_{n-1} = x^*\) as long as \(n\) and \(m\) are independent integers. The concept of subsequences is also clarified, confirming that any subsequence converging to \(x^*\) reinforces the original limit statement.
PREREQUISITESMathematics students, educators, and anyone interested in advanced calculus or real analysis, particularly those studying limits and convergence of sequences.
ozkan12 said:if $\lim_{{n}\to{\infty}} {y}_{m+1}={x}^{*}$, Can we say that $\lim_{{n}\to{\infty}} {y}_{n-1}={x}^{*}$...Please pay attention, I say m and n...
If
$$\lim_{m\to\infty}y_{m+1}=x^*,$$
can we say that
$$\lim_{n\to\infty}y_{n-1}=x^*?$$