MHB Limits of x* when n and m Approach Infinity

ozkan12
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if $\lim_{{n}\to{\infty}} {y}_{m+1}={x}^{*}$, Can we say that $\lim_{{n}\to{\infty}} {y}_{n-1}={x}^{*}$...Please pay attention, I say m and n...
 
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ozkan12 said:
if $\lim_{{n}\to{\infty}} {y}_{m+1}={x}^{*}$, Can we say that $\lim_{{n}\to{\infty}} {y}_{n-1}={x}^{*}$...Please pay attention, I say m and n...

Did you mean to write

If
$$\lim_{m\to\infty}y_{m+1}=x^*,$$
can we say that
$$\lim_{n\to\infty}y_{n-1}=x^*?$$

Because, if so, the answer is yes, if $n$ and $m$ are just independent integers going to infinity. The variable used in the limit is just like a "dummy variable". You can also show that if $n$ is an arbitrary integer, and
$$\lim_{n\to\infty}y_n=x^*,$$
then any subsequence must also converge:
$$\lim_{m\to\infty}y_{n_m}=x^*.$$
 
Dear Ackbach

How if $\lim_{{m}\to{\infty}} {y}_{m+1}={x}^{*}$ we can say that $\lim_{{n}\to{\infty}} {y}_{n}={x}^{*}$ ? I didnt understand...Please can you explain...Thank you for your attention
 
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We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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