[LinAlg] Show that T:C[a,b] -> R is a linear transformation

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SUMMARY

The discussion centers on proving that the transformation T: C[a,b] -> R defined by T(f) = ∫(from a to b) f(x)dx is a linear transformation. The proof confirms that T satisfies the properties of linearity: T(f + g) = T(f) + T(g) and T(cf) = cT(f) for all functions f, g in C[a,b] and scalars c. Participants emphasize the simplicity of the proof and suggest using LaTeX for clearer mathematical representation.

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Homework Statement


Show that T:C[a,b] -> defined by T(f) = ∫(from a to b) f(x)dx is a linear transformation.

Homework Equations


Definition of a linear transformation:
A linear transformation T from a vector space V into a vector space W is a rule that assigns to each vector x in V a unique vector T(x) in W, such that
i. T(u+v) = T(u) + T(v) for all u, v in V, and
ii. T(cu) = cT(u) for all u in V and all scalars c

The Attempt at a Solution


In order for this mapping to be a linear transformation it must follow the above rules, so
i. T(f + g) = ∫ [f(x) + g(x)]dx = ∫ f(x)dx + ∫ g(x)dx = T(f) + T(g)
ii. T(cf) = ∫ cf(x)dx = c∫ f(x)dx = cT(x)
Is it really that simple or did I over simplify the problem?

This problem is not taken from any book (afaik) and doesn't resemble much that we've done in class or from the book so it's throwing me off a bit as I bend my brain to look at things from different angles trying to make sure that I don't miss anything.
 
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PeroK said:
Yes, it really is as simple as that.

You should try to learn a bit of Latex:

https://www.physicsforums.com/help/latexhelp/

For example:

##\int_a^b f(x)dx##

Looks a lot better!

It does! I'll look into that. Thanks!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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