Linear Differential Operator/Inner Product

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SUMMARY

The discussion centers on demonstrating the symmetry of the linear differential operator L defined as L = -x*(d^2/dx^2) - (2-x)*(d/dx) with respect to the inner product = ∫(x*e^(-x)*f(x)*g(x), x=0..∞) on the vector space V of all real polynomials. Participants confirm that to show symmetry, one must verify that = for polynomials f and g. The approach involves substituting Lf(x) into the integral for and similarly for .

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  • Understanding of linear differential operators
  • Familiarity with inner product spaces
  • Knowledge of polynomial functions
  • Basic calculus, specifically integration techniques
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  • Learn about inner product spaces and their applications in polynomial analysis
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Mathematicians, students studying functional analysis, and anyone interested in the properties of differential operators and inner product spaces.

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Can anyone help me?

Q. An inner product is defined on the vector space V of all (real) polynomials (of arbitrary
degree) by

<f,g>=Int(x*e^(-x)*f(x)*g(x),x=o..infinity

Show that the linear differential operator

L=-x*(d^2/dx^2)-(2-x)*(d/dx):V->V

is symmetric with respect to this inner product.Don't necessarily need the exact answer, just need to know how I'm meant to go about it.
 
Last edited:
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Akers said:
Can anyone help me?

Q. An inner product is defined on the vector space V of all (real) polynomials (of arbitrary
degree) by

<f,g>=Int(x*e^(-x)*f(x)*g(x),x=o..infinity

Show that the linear differential operator

L=-x*(d^2/dx^2)-(2-x)*(d/dx):V->V

is symmetric with respect to this inner product.


Don't necessarily need the exact answer, just need to know how I'm meant to go about it.

Let f and g be a polynomials. Show that <Lf, g>= <f, Lg>.
 
HallsofIvy said:
Let f and g be a polynomials. Show that <Lf, g>= <f, Lg>.

Ah right, thanks.

So all I need to do is replace the f(x) in the integral with Lf(x) (and the same with g(x) on the other side)? I'll give it a go anyway. Cheers.
 

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