Linear recurrence with polynomial coefficients

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SUMMARY

The discussion centers on solving a linear recurrence with polynomial coefficients, specifically the equation: i (i - 1) (i - 2) b[i] = 1/3 (i + 1) i (1 - i) b[i - 3] + (1 + i) i (i - 2) b[i - 2] + (i + 1) (i - 1) (i - 2) b[i - 1]. The participant, Pere, seeks a general theory or algorithm for such recursions. A substitution method, b[i] = (i + 1)c[i], simplifies the equation significantly, indicating a potential pathway to a solution.

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  • Understanding of linear recurrences
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Pere Callahan
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Hi all,

I came across a linear recurrence with polynomial coefficients and realized that I don't have a clue as to how to solve it. The usual methods like generating functions or guessing seem not to work in that case.

Here is the equation:

<br /> i (i - 1) (i - 2) b<i> = 1/3 (i + 1) i (1 - i) b[i - 3] + (1 + i) i (i - 2) b[i - 2] + (i + 1) (i - 1) (i - 2) b[i - 1]<br /> </i>


Is there any general theory on recursions of that type or maybe even a general algorithm to compute the solution (in terms of some initial valeus b[0], b[1], b[2])?

Thanks a lot!

Pere
 
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So, for this particular recursion, the substitution b<i>\mapsto(i+1)c</i> reduces the equation to a very easy form. The question about the general theory remains.
 
Last edited:

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