Linear spring and non-linear spring

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The discussion focuses on calculating the maximum deflection of a spring when a 5 kg mass is placed on it. For a linear spring with a constant of 3000 N/m, the initial calculation yields a deflection of 16.35 mm, which is noted as only half of the expected answer. Participants discuss the approach to solving the problem, emphasizing the importance of understanding work and energy principles in dynamics. The nonlinear spring is introduced with a more complex force equation, prompting a request for guidance on how to approach its calculation. Overall, the conversation highlights the need for a solid grasp of physics concepts to solve these spring deflection problems effectively.
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Homework Statement


If a delicate istrument havng a mas of 5 kg is placed on a springof length L so tha its base just touches the undeformed spring and then inadvertly released from the position, determine the maximum deflection xm of the spring assuming (a) linear spring constant k=3000N/m (b) a hard, nonlinear spring, for which F=3000N/m(x+160x3)


Homework Equations


F=-k(dx)


The Attempt at a Solution


5*9.81/3000=16.35 mm this is half of the answer why is that?

Also can someone point me in te right direction for the nonlinear spring, that would be great.
 
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Are you in a calc based physics class, or an algebra based class? And do you have an understanding of conservation of energy yet? Or just work = force x displacment?
 
I understand all of the mentione above, I am in EGN3400 aka Dynamics. But this is a very basic problem.
 
To solve this particular problem... Work is force times displacement, and change in kinetic energy is equal to work. Think about the initial and final kinetic energies for the falling mass, and set that equal to the work done by the variable forces.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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