Linearly Independent: Is {u1,u2,u3}?

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SUMMARY

The discussion centers on the linear independence of the set {u1, u2, u3} given that the pairs {u1, u2}, {u2, u3}, and {u1, u3} are linearly independent. It is established that this does not guarantee the linear independence of the entire set {u1, u2, u3}. Counterexamples exist in R^2, demonstrating that even with pairwise linear independence, the entire set can still be linearly dependent. Participants are encouraged to explore specific counterexamples and consider the implications of orthogonal standard basis vectors.

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Homework Statement



If u1 and u2, u2 and u3, u1 and u3 are Linearly Independent, does it follow that {u1,u2,u3} is Linearly Independent?
 
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It helps if you write it out as follows:
a_1 u_1 + a_2 u_2 + a_3 u_3 = \textbf{0}.

Suppose one of the ai's is non-zero. Can you derive a contradiction with what you are given? Then, next suppose 2 of the coefficients are non-zero. Apply the same consideration.
 
symsane said:

Homework Statement



If u1 and u2, u2 and u3, u1 and u3 are Linearly Independent, does it follow that {u1,u2,u3} is Linearly Independent?

No. Try to find a counterexample (this is possible in R^2).
 
Try this first
if u1 and u2 are linearly dependent does it follow that
v1 and v2 are linearly independent where
v1=a*u1+b*u2
v2=c*u1+d*u2

or

if span(V)=n
does that mean any n vectors are linearly independent?
 
yyat said:
No. Try to find a counterexample (this is possible in R^2).
Oops, can't believe I missed such a simple counter-example.
 
yyat said:
No. Try to find a counterexample (this is possible in R^2).


I could not find a counter example. I think it is LI.
 
In R^2 there are zillions of counterexamples where v1, v2, and v3, are pairwise linearly independent. If you can't find any, you aren't looking very hard.
 
symsane said:
I could not find a counter example. I think it is LI.
You can try thinking about the orthogonal standard basis vectors.
 

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