Show that matrix A is not invertible by finding non trivial solutions

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Homework Help Overview

The problem involves a 3x3 matrix A, which is defined as the sum of two matrices B and C. Matrix B has identical rows represented by a vector u, and matrix C has identical columns represented by a vector v. The task is to demonstrate that matrix A is not invertible by identifying non-trivial solutions to the equations Bx = 0 and Cx = 0.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the nature of the solutions to the homogeneous equations Bx = 0 and Cx = 0, considering the implications of invertibility and the structure of the matrices.

Discussion Status

There is an ongoing exploration of the properties of matrices B and C, with some participants questioning their invertibility and discussing the implications of linear dependence. Guidance has been offered regarding the elimination process and the nature of solutions.

Contextual Notes

Participants are considering the implications of Gaussian elimination and determinants in relation to the matrices' structures and their invertibility. There is an acknowledgment of the need for non-trivial solutions in the context of the problem.

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Homework Statement



The 3x3 matrix A is given as the sum of two other 3x3 matrices B and C satisfying:1) all rows of B are the same vector u and 2) all columns of C are the same vector v.

Show that A is not invertible. One possible approach is to explain why there is a nonzero vector x satisfying both Bx = 0 and Cx = 0.

^^I'm having a hard time seeing why Bx=0 and Cx=0 should have nonzero solutions. I envision a matrix {{u1,u2,u3},{u1,u2,u3},{u1,u2,u3}} * some column vector = 0 but I'm just not seeing how to go about this when u1,u2,u3 could be anything.


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The Attempt at a Solution

 
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Bx=0 and Cx=0 are homogeneous system of equations. So there are only two posibilities for their solutions. 1. Either the solutions are trivial and unique or 2. Infinitely many solutions.

Ask yourself if B is invertible? If it is, then multiply both sides of Bx=0 by its inverse to obtain only the trivial solution exists. If A is not invertible, then it must case 2.

Let me know if it helps.
 


hmm, you've given me something to think about. So I can see how B is not invertible because well Gaussian elimination on it fails, but what about C? I don't think you can immediately see it by trying to do the more familiar elimination steps, so is it enough to say that in a way it a dependent matrix?
 


Try writing out Cx=0 explicitly.
 


I am not sure what you mean by elemination failing. However, elimination give many rows of zero and hence infinitely many solutions for Bx=0. Consider doing elimination on C for a 2x2 matrix with the same columns and see what are your solutions.

If you have learn the determinant, then the determinant also gives you the answer imeddiately.
 


First of all, what do you know about a matrix that has linearly dependent row or column vectors?
 


vela said:
Try writing out Cx=0 explicitly.

oh I see, if you try to eliminate one you end up eliminating all the others in the row as well
 


lmedin02 said:
I am not sure what you mean by elemination failing. However, elimination give many rows of zero and hence infinitely many solutions for Bx=0. Consider doing elimination on C for a 2x2 matrix with the same columns and see what are your solutions.

If you have learn the determinant, then the determinant also gives you the answer imeddiately.

Sorry, I should have been more clear. That is what I meant.
 


Ok. I think I got it. Thank you all for your quick replies!
 

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