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Liquid Drop Model of the Nucleus

  1. May 10, 2009 #1
    Looking at the liquid drop model of the nucleus and the semi-empirical formula for the atomic mass of the nucleus.

    I understand the formula but I'm trying to figure out why some nuclei are unstable against both beta- and beta+ decay. Any ideas? I assume it's something to do with the symmetry term?
     
  2. jcsd
  3. May 10, 2009 #2
    Are you talking about stable nuclei, or those that decay only by k-shell electron capture?
     
  4. May 10, 2009 #3
    Hi Bob,

    Im talking about a nucleus that can undergoe either b+ or b- decay. There is a way of showing some can decay either way but i cant see it from the liquid drop model....the semi emperical formula can give mass and binding energy, the more i look into it the more i think that its the binding energy that will determine if it decays, but doesnt say whether it can decay by b+ or b-, or in my case both...

    I hope that makes it a little clearer!
     
  5. May 10, 2009 #4
    Here is what Wikipedia says about copper 64, an odd-odd nucleus that can decay by either electron (beta-) decay, positron (beta+) decay, or k-shell electron-capture. So Cu-64 decays 3 ways.

    Wiki says
    64Cu has a half-life of 12.701 ± 0.002 hours and decays by 17.86 (± 0.14)% by positron emission, 39.0 (± 0.3)% by beta decay, 43.075 (± 0.500)% by electron capture and 0.475 (± 0.010)% gamma radiation/internal conversion. These emissions are 0.5787 (± 0.0009) and 0.6531 (± 0.0002) MeV for positron and beta respectively and 1.35477 (± 0.00016) MeV for gamma.
     
  6. May 11, 2009 #5

    malawi_glenn

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  7. May 11, 2009 #6

    Vanadium 50

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    Nuclei that can beta decay in either direction (Cu-64 is an example, as is V-50) will do so if it is energetically favorable to do so. This normally happens when the parent nucleus is doubly odd - high spin helps as well. This gives a large energy gap with respect to the daughters.
     
  8. May 11, 2009 #7
    Cheers for the answers, helped me alot!
     
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