joel ogundeji
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i am student of ladoke akitola university of technology ogbomosho oyo state Nigeria . help me on this question log^18-log^10=19
Logarithm Ques: LAUTECH Student Needs Help
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I don't see a question here! What is the question?
Also what does "log^18" mean? I that just log(18)? And is that common log (base 10) or natural log (base e)? Or is the problem to find base a such that loga(18)- loga(10)= 19?
If that is the case, you can simplify by using the fact that loga(18)- loga(10)= loga(18/10)= loga(9/5) and then you are trying to find a such that a19= 9/5.
Also what does "log^18" mean? I that just log(18)? And is that common log (base 10) or natural log (base e)? Or is the problem to find base a such that loga(18)- loga(10)= 19?
If that is the case, you can simplify by using the fact that loga(18)- loga(10)= loga(18/10)= loga(9/5) and then you are trying to find a such that a19= 9/5.
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