Logarithm Ques: LAUTECH Student Needs Help

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SUMMARY

The discussion centers on a logarithmic equation posed by a student from Ladoke Akintola University of Technology, specifically the expression log18 - log10 = 19. Participants clarify that "log18" likely refers to log(18) and question whether it is a common logarithm (base 10) or a natural logarithm (base e). The solution involves simplifying the expression using the logarithmic identity loga(x) - loga(y) = loga(x/y), leading to the equation a19 = 9/5 to find the base a.

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joel ogundeji
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i am student of ladoke akitola university of technology ogbomosho oyo state Nigeria . help me on this question log^18-log^10=19
 
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I don't see a question here! What is the question?

Also what does "log^18" mean? I that just log(18)? And is that common log (base 10) or natural log (base e)? Or is the problem to find base a such that loga(18)- loga(10)= 19?

If that is the case, you can simplify by using the fact that loga(18)- loga(10)= loga(18/10)= loga(9/5) and then you are trying to find a such that a19= 9/5.
 

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