Logging 12*e3c: Is ln(e) Cancelled Out?

[Alexx1]

If you have to take the log of 12*e^3c
Can I do it like this: 12*ln(e^3c)?
So ln e fall away, so the result is: 12*3c = 36c
Or do I have to do it like this: ln(12*e^3c?

I'm not sure of it.

 

[Mentallic]

Use the rule that $log(ab)=log(a)+log(b)$ and I'm sure things should fall into place

 

[Alexx1]

Use the rule that $log(ab)=log(a)+log(b)$ and I'm sure things should fall into place

Thanks

 

[Mentallic]

No problem