- #1
Alexx1
- 86
- 0
If you have to take the log of 12*e^{3c}
Can I do it like this: 12*ln(e^{3c})?
So ln e fall away, so the result is: 12*3c = 36c
Or do I have to do it like this: ln(12*e^{3c}?
I'm not sure of it.
Can I do it like this: 12*ln(e^{3c})?
So ln e fall away, so the result is: 12*3c = 36c
Or do I have to do it like this: ln(12*e^{3c}?
I'm not sure of it.