Long desk with one end cut, falls from the other one

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SUMMARY

The discussion focuses on calculating the final velocity of a second desk (mass m2) when a long desk (mass m1) with one end angled at 45 degrees falls from the other end. The problem involves applying Newton's second law (F=ma) and the moment of inertia formula for a thin long rod (Io=1/12ml^2). The user seeks guidance on how to incorporate the moment of inertia into their calculations, indicating a need for a deeper understanding of rotational dynamics in this context.

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Homework Statement


Picture of problem : http://screenshot.sh/ouZAbUeL9Qzmj We have got a desk,mass m1, length L1 and thickness d, and L1>>d. One of it's ends is angled by 45 degree. At the beginning it is put on the other desk which thickness is also d and mass is m2. I have to find final velocity of the second desk, this one which is lying on the table. We skip friction. I also have information at the end of the task that Moment of inertia of thin long rod, length l, and mass m is 1/12ml^2.

Homework Equations


Io=1/12ml^2
F=ma.

The Attempt at a Solution


I don't really have any idea how to approach this task. What i could is just simply mark all the forces, just what i do every time when i do this kind of question (i mean, i have some mass and i have to find accelerate, whole basically based on 2nd Newton law's), but it didnt help. I ve only found that sin of the angle between first desk and the table is sin=d/L1-d. The biggest problem i think is that i don't know how to use info about moment of inertia in this question. If you can explain to me, how to approach this one and how to use moment of inertia i would be grateful. Thanks in advance,

PS. I am posting on advanced becouse nobody answered me on introductory.
 
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