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- How to calculate total gas volume for each cylinder based on the consumption ratio of oxy/fuel for cutting torches

For one of our projects we are at present using quite large amounts of gas & oxygen.

What I was trying to figure out was how to calculate the total available amount of gas in a cylinder (be that either Propane/Oxygen or Propylene (Propene)) and then to determine whether or not -given a certain number of cylinders of each- do we have sufficient gas in stock based on their relative consumption ratio.

For example:

we may have 1 oxygen quad (i.e. interconnected cylinders) with 9 cylinders, type: G/G2, with a 50ltr water-volume @ 150bar filling pressure.

we have propane cylinders, type: S/SE, with a 108ltr water-volume @ 10bar filling pressure.

Given that the oxy/fuel consumption ratio when cutting steel for oxygen vs propane is ± 4:1, how many cylinders of propane would I need to end up with an exact ratio between oxygen and propane?

Can I simply use normal gas laws here?

I.e. oxygen, 9 cylinders, each with a volume 50ltr @ 150bar = 67500ltr of oxygen?

and, subsequently for propane, volume 108ltr @ 10 bar = 1080ltr of propane?

i.e. in that case I would need 16 cylinders of propane?

(9 x (150 x 50)) = 67500ltr @ 4:1 = 16875ltr of propane required => 16875 / 1080 = 15.6 = 16 cylinders?

Would that be a correct approach or would I need to take into account a different volume for each gas based on the fact that the propane and oxygen go through a phase transition in the cylinder (i.e. they go from liquid to gas)

Any help would be appreciated.

What I was trying to figure out was how to calculate the total available amount of gas in a cylinder (be that either Propane/Oxygen or Propylene (Propene)) and then to determine whether or not -given a certain number of cylinders of each- do we have sufficient gas in stock based on their relative consumption ratio.

For example:

we may have 1 oxygen quad (i.e. interconnected cylinders) with 9 cylinders, type: G/G2, with a 50ltr water-volume @ 150bar filling pressure.

we have propane cylinders, type: S/SE, with a 108ltr water-volume @ 10bar filling pressure.

Given that the oxy/fuel consumption ratio when cutting steel for oxygen vs propane is ± 4:1, how many cylinders of propane would I need to end up with an exact ratio between oxygen and propane?

Can I simply use normal gas laws here?

I.e. oxygen, 9 cylinders, each with a volume 50ltr @ 150bar = 67500ltr of oxygen?

and, subsequently for propane, volume 108ltr @ 10 bar = 1080ltr of propane?

i.e. in that case I would need 16 cylinders of propane?

(9 x (150 x 50)) = 67500ltr @ 4:1 = 16875ltr of propane required => 16875 / 1080 = 15.6 = 16 cylinders?

Would that be a correct approach or would I need to take into account a different volume for each gas based on the fact that the propane and oxygen go through a phase transition in the cylinder (i.e. they go from liquid to gas)

Any help would be appreciated.