LS coupling and calculating the total angular momentum

Click For Summary
SUMMARY

The discussion focuses on calculating total angular momentum (J) in many-electron atoms using LS coupling and the spin-orbit effect, as outlined in Arthur Beiser's "Perspective of Modern Physics." Given the values of orbital angular momentum (L=2) and spin angular momentum (S=1), the configurations for J can be determined using the quantum mechanical rule for angular momentum addition. The possible values for J are calculated as J = L + S, L + S - 1, ..., |L - S|, resulting in J values of 3, 2, and 1.

PREREQUISITES
  • Understanding of LS coupling in quantum mechanics
  • Familiarity with angular momentum in quantum systems
  • Knowledge of spin and orbital angular momentum concepts
  • Basic grasp of quantum mechanics principles
NEXT STEPS
  • Study the addition of angular momenta in quantum mechanics
  • Explore the implications of spin-orbit coupling in atomic physics
  • Learn about the quantum mechanical treatment of many-electron atoms
  • Investigate the role of total angular momentum in spectroscopy
USEFUL FOR

Students and professionals in physics, particularly those studying quantum mechanics, atomic structure, and angular momentum in many-electron systems.

cooper607
Messages
49
Reaction score
0
hi all, these days i m going through Arther Beiser's modern physics book where i read about the total angular momentum in many electron atoms..now i could understand the LS coupling and spin orbit effect how they combine to form total angular momentum but if i m given the magnitude of L=2 (orbital angular momentum ) and S=1 (spin angular momentum)

then how can i calculate the configurations they can have and also how can i calculate the J(total angular momentum ) for each configuration ...please help me anyone... i m referring from BESISER'S "PERSPECTIVE OF MODERN PHYSICS "
 
Physics news on Phys.org
The general rule for addition of angular momenta in quantum mechanics is, for ##J=L+S##,
$$
J = L+S, L+S-1, \ldots, \left| L - S \right|
$$
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
2
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K