Magnetic Field at the Center of a Coil

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To determine the magnetic field at the center of a coil with a radius of 0.22m carrying a 200 A current, the relevant formula is B = (4pi*10^-7)I / 2R. Additionally, a long straight wire carrying a 310 A current affects the magnetic field at the coil's center, calculated using B = (4pi*10^-7)I / 2*pi*r. The total magnetic field is the sum of the fields from both the coil and the straight wire. There is some confusion regarding whether the straight wire's field influences the coil's center, as it may not penetrate the coil's interior. Ultimately, the correct approach is to add both magnetic fields together to find the total value in gauss.
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Homework Statement


The radius of a single coil of wire is 0.22m. It carries a 200 A current that flows clockwise.
A long, straight wire carrying a current of 310 A toward the right is located 0.05m from the edge of the coil. What is the value of the magnetic field at the center of the coil? Answer should be in gauss. (1Tesla = 10,000 gauss)

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Homework Equations


Magnetic field at the center of a flat circular coil: B = (4pi*10^-7)I / 2R
Magnetic field created by a long strait wire: B = (4pi*10^-7)I / 2*pi*r


The Attempt at a Solution


The way i think about this problem is this: I know the wire will create its own magnetic field, this field will extend into the field created by the coil, thus increasing the total magnetic field. I solved for B created by the long straight wire, then solved for the B created by the flat circular coil. Next, i added the two magnetic fields together and converted T's to g's.
 
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But doesn't conductors shield their interiors?
So, that means the outer straight wire has no effect @ the center of the coiled wire?
 
I'm not sure, but i know if i only calculate the field for the loop i get 5.7 gauss which is not the correct answer.
 
I think you are right, just add two of them because they are parallel.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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