Magnetic field between two wires (vector sums)

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SUMMARY

The discussion centers on calculating the magnetic field halfway between two parallel wires carrying currents I and 2I in opposite directions. The solution involves applying Ampere's Law, which states that the magnetic field B around a wire is given by B = μI / (2πr), where μ is the permeability of free space and r is the distance from the wire. The confusion arises from the application of vector addition to the magnetic fields generated by each wire, as Ampere's Law describes the contribution of currents enclosed by the Amperian loop, leading to a conceptual challenge in understanding how to combine the magnetic fields from both wires.

PREREQUISITES
  • Understanding of Ampere's Law and its mathematical formulation
  • Knowledge of magnetic field concepts and vector addition
  • Familiarity with the permeability of free space (μ)
  • Basic principles of electromagnetism and current-carrying conductors
NEXT STEPS
  • Study the application of Ampere's Law in different geometries
  • Learn about the superposition principle in magnetic fields
  • Explore the concept of magnetic field lines and their interactions
  • Investigate the effects of varying current magnitudes on magnetic fields
USEFUL FOR

Students and educators in physics, particularly those focusing on electromagnetism, as well as anyone seeking to deepen their understanding of magnetic fields generated by current-carrying wires.

quantum13
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Homework Statement


Two parallel wires carry a current I and 2I in different directions. What is the magnetic field halfway between the two wires?


Homework Equations


Ampere's law
Int (B dot dA) = permissivity x enclosed current

The Attempt at a Solution


Draw a circle around wire 1
B x 2 pi r = mu x I
B = mu x I / 2 pi r
if d = distance between two wires, r = d/2


Where I'm confused is at the part where I add the two B vectors to find the total B. According to the rule of vector addition, I can add vectors to find the net vector. BUT I thought Ampere's law was supposed to describe all of the B at a point as proportional to ONLY the current inside and that currents outside the Amperian loop were not supposed to make any net contribution to B. So how can I add together two vectors when Ampere's law is supposed to describe a magnetic field with all the B vectors already added up? This is a more conceptual question. Thanks.
 
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Hi quantum13! :smile:

(have a mu: µ and a pi: π and btw, it's permeability for magnetism :wink:)
quantum13 said:
BUT I thought Ampere's law was supposed to describe all of the B at a point as proportional to ONLY the current inside and that currents outside the Amperian loop were not supposed to make any net contribution to B. So how can I add together two vectors when Ampere's law is supposed to describe a magnetic field with all the B vectors already added up? This is a more conceptual question. Thanks.

You have to look at the whole loop.

A loop C around a wire with currrent I1 and field B1 has an integral of ∫C B1.dl = 2πrB1 = µ0I1.

The same loop has an integral of ∫C B2.dl for a different wire, but B2 will not be constant, and if this wire lies outside C, the integral is zero. :wink:
 
hooray another annoying and difficult realization in the land of physics :)


thanks
 

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