Magnetic Field inside and external to a wire

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SUMMARY

The discussion focuses on deriving the magnetic field inside and outside a wire with a varying current density, specifically J = br, where b is a constant. The derived expressions for the magnetic field at radial distances r1 (inside the wire) and r2 (outside the wire) are B = (u*b*r1^2)/2 and B = (u*b*R^3)/(2*r2), respectively. However, the correct expressions are B = (u*b*r1^2)/3 for r1 and B = (u*b*R^3)/(3*r2) for r2, indicating that integration of the current density is necessary to obtain the correct results.

PREREQUISITES
  • Understanding of Ampère's Law
  • Familiarity with magnetic permeability (u)
  • Knowledge of integration techniques in physics
  • Basic concepts of current density and its relation to area
NEXT STEPS
  • Study the application of Ampère's Law in cylindrical coordinates
  • Learn about magnetic fields generated by current-carrying conductors
  • Explore integration techniques for calculating magnetic fields
  • Investigate the concept of current density and its implications in electromagnetism
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Physics students, electrical engineers, and anyone interested in electromagnetism and the behavior of magnetic fields in conductive materials.

Gear300
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I again bring a question: If a wire of radius R carries a current density J = br (r is radius and b is a constant), in which J = I/A (A is area)...then derive an expression for the magnetic field at r1 (r1 being a radial distance less than R) and at r2 (r2 being a radial distance greater than R).

My answer at r1 is B = (u*b*r1^2)/2 and at r2 is B = (u*b*R^3)/(2*r2), in which u is the permeability of free space.
The actual answer at r1 is B = (u*b*r1^2)/3 and for r2 is B = (u*b*R^3)/(3*r2)...which seem to match my answers...just instead of halving each one...its divided by 3...how did they get that?
 
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Actually...nevermind...I found out why...I apparently had to integrate for increments of I.
 

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