Magnetic force and radius from magnetic field

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SUMMARY

The discussion focuses on calculating the magnetic force on an electron moving in a magnetic field of 0.0200 T and determining the radius of its circular path. The magnetic force is calculated using the equation F=qvB, where q is the charge of the electron, v is its velocity (5.00x10^6 m/s), and B is the magnetic field strength. The radius of the circular path is derived from the equation F=kq/r^2, where k is a constant related to the force and charge. These calculations are essential for understanding the behavior of charged particles in magnetic fields.

PREREQUISITES
  • Understanding of electromagnetic theory
  • Familiarity with the Lorentz force equation
  • Knowledge of circular motion dynamics
  • Basic grasp of electron properties and charge
NEXT STEPS
  • Study the Lorentz force and its applications in particle physics
  • Learn about the motion of charged particles in magnetic fields
  • Explore the concept of magnetic field strength and its measurement
  • Investigate the relationship between force, charge, and radius in circular motion
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Physics students, educators, and anyone interested in the principles of electromagnetism and the behavior of charged particles in magnetic fields.

adambahh
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A magnetic field of 0.0200 T (up) is created in a region

a)find initial magnetic force on an electron initially moving at 5.00x10^6 m/s (N) in the field

b) what is the radius of the circular path

Equations used:
a) F=qvB
b) F= kq/r^2

Thanks in advance
 
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