Magnetic Reductor: Questions & Answers

  • Thread starter Cri85
  • Start date
  • Tags
    Magnetic
In summary: It is possible to use a reductor with magnets using the equations provided. The efficiency of the reductor is 1 if the magnets do not lose heat. The angular velocity of the reductor is not constant, but the mean angular velocity is at w.
  • #1
68
0

Homework Statement



It is a question I asked to myself.

I studied the induction motor at school, and I asked to the teacher if it's possible to use magnets for build a reductor with magnets. She said it's possible but the energy lost in heating will be very high. I would like to know if my forces are correct and how to estimate the losses.

http://imageshack.com/a/img537/1866/zqaJ3k.png [Broken]

The Rotor1 rotates at 3w clockwise from an external device not drawn. The Rotor2 is push by the Rotor1. I guess the radius of the Rotor1 is 1 and the radius of the Rotor2 is 3. I would like to have w for the Rotor2, but I'm not sure if it is possible.

I have some questions:

1) I think it's possible to use it only if I start the device like I drawn, correct ? The magnet is pushing clockwise the Rotor2: the Rotor2 is acccelarating, the Rotor2 gives an energy to an external device (not drawn), magnets push counterclockwise the Rotor2: it is decelerating. The angular velocity of the Rotor2 is not constant but the mean can be at w, no ?

2) Losses are very high, even w is low ? How to estimate them ? In theory is it possible to have an efficiency of 1 with this reductor ?

3) Maybe this device exist, have you a link ?

Homework Equations



--

The Attempt at a Solution



I drawn forces:

http://imageshack.com/a/img901/3278/NOjZYC.png [Broken]

My forces are correct ? The Rotor1 gives an energy F*r*3w*t and the Rotor2 can give F*3r*w*t, the efficiency can be at 1 only if magnets don't lost heating.

For me the angular velocity is not constant but like:

http://imageshack.com/a/img540/668/Pd5ALz.png [Broken]
 
Last edited by a moderator:
Physics news on Phys.org
  • #2
If the inner rotor is turning steadily at constant angular velocity, I think the outer one will turn steadily at the same angular velocity. I picture an equilibrium where the N on the inner magnet is just a little closer to the outer N on the forward side than to the outer N on the reverse side. Just enough closer so the larger force forward is just enough to overcome whatever air and friction resistances are involved.

I don't think there would be very much energy loss to friction with decent bearings so very little torque and rotational energy would be needed to keep it moving steadily. Anyone who has chased a magnet around with another magnet will have a good feel for this efficiency. Odd, I seem to recall doing this as a child with one magnet on a table top and the other under the table top, yet there wouldn't have been sufficiently strong magnets over 50 years ago. Maybe tabletops were thinner.

Interesting application:
http://www.magnomatics.com/technology/magnetic-gears.aspx [Broken]
 
Last edited by a moderator:
  • #3
For me the angular velocity of the Rotor2 is lower than the Rotor1 because the Rotor1 gives an energy F*3*w*t (the radius is R1=1 and the angular velocity is 3w), so the Rotor2 must give the same energy, like the radius is R2=3 and the force is the same, w must be lower no ?
 
  • #4
I see your point. Like an automatic transmission torque converter. When a lot of output torque is needed, you have to run the engine faster to provide the necessary output power. However, with the magnetic coupling my mind sees catastrophic failure when the inner ring goes out of sync with the outer one. As the Inner N passes the outer N, there is no torque on the outer ring for a moment, then reverse torque for about as long as there will be forward torque.

Too complicated for me, I guess.
 
  • #5
Delphi51 said:
Like an automatic transmission torque converter.
Yes like that. Thanks for your help.
 

1. What is a magnetic reductor?

A magnetic reductor is a device that is used to reduce the strength of a magnetic field. It typically consists of a coil of wire that is used to create a magnetic field, and a ferromagnetic core that is used to amplify or reduce the strength of the field.

2. How does a magnetic reductor work?

A magnetic reductor works by using the principles of electromagnetic induction. When an electric current flows through the coil, it creates a magnetic field. This magnetic field then interacts with the ferromagnetic core, causing it to either amplify or reduce the strength of the field.

3. What are the applications of a magnetic reductor?

A magnetic reductor has a wide range of applications, including in power systems, electric motors, and transformers. It can also be used in scientific experiments and research, such as in particle accelerators and magnetic resonance imaging (MRI) machines.

4. How is a magnetic reductor different from an electromagnet?

While both a magnetic reductor and an electromagnet use electric currents to create magnetic fields, they have different purposes. A magnetic reductor is designed to reduce the strength of a magnetic field, while an electromagnet is used to create a strong magnetic field for specific applications.

5. Are there any safety concerns when using a magnetic reductor?

Yes, it is important to take proper safety precautions when using a magnetic reductor. The magnetic field created by the device can be strong enough to affect electronic devices and can also be harmful to individuals with certain medical conditions, such as pacemakers. It is important to follow manufacturer instructions and guidelines when using a magnetic reductor.

Suggested for: Magnetic Reductor: Questions & Answers

Replies
6
Views
213
Replies
12
Views
88
Replies
4
Views
784
Replies
17
Views
239
Replies
31
Views
926
Replies
3
Views
230
Replies
5
Views
118
Replies
3
Views
864
Replies
11
Views
313
Back
Top