Magnitude of a velocity vector with special relativity

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SUMMARY

The discussion focuses on the calculation of velocity vectors in the context of special relativity. It highlights that the formula for determining the magnitude of a velocity vector remains unchanged from classical mechanics, expressed as v^2 = v_x^2 + v_y^2 + v_z^2. The participants clarify that the special relativity rules for adding relative velocities do not alter the method for decomposing a single velocity vector into its components. Thus, the same formula applies regardless of the relativistic context.

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Froskoy
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Hi,

I'm trying to get my head around how velocity vectors work in special relativity. For example, in classical mechanics, the magnitude of the velocity would be given by:

v^2 = \sqrt{v_x^2 + v_y^2 + v_z^2}

where v_x, v_y and v_z are the x, y and z components of the velocity respectively.

What is the equivalent formula for use in special relativity. For example, if you knew the magnitude of the velocity, v and the x component of the velocity, what formula would you use to work out the y component?

With very many thanks,

Froskoy.
 
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Hi Froskoy! :wink:
Froskoy said:
… if you knew the magnitude of the velocity, v and the x component of the velocity, what formula would you use to work out the y component?

same formula! :smile:

the special relativity rule for adding relative velocities has nothing to do with "de-componenting" a single velocity :wink:
 

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