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Homework Statement
A square loop consists of a single turn with a resistance of 4.00 Ω. The loop has an area of 600 cm^2, and has a uniform magnetic field passing through it that is directed out of the page. The loop contains a 12-volt battery, connected as shown in the figure below.
C:\Users\Michael\Pictures\20-p-044.gif
At the instant shown in the figure, there is no net current in the loop. At what rate is the magnitude of the magnetic field changing?
Homework Equations
Φ=BAcosθ
ε=-NΔΦ/Δt
The Attempt at a Solution
ε=-NΔΦ/Δt
ε=-NΔBAcosθ/Δt, A is constant so
ε=-NAΔB/Δt
ΔB/Δt=ε/NA, negative sign is removed because only magnitude is asked for.
ΔB/Δt=12V/(1)(0.06m^2)=200T/s
I worked this out and it turned out to be wrong. I put in 12V as the emf as I thought that the total voltage should be the same as there is no net current in the loop, however that is the only part of the problem that I am uncertain about. The answer must be in T/s.
Thank you in advance for the help.