What Rate of Magnetic Field Change Induces a 10 A Current in a Circular Loop?

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SUMMARY

The discussion focuses on calculating the rate of change of a magnetic field required to induce a 10 A current in a circular loop with a diameter of 18 cm, formed from wire with a diameter of 5.0 mm and a resistivity of 1.69 × 10-8 Ω·m. The induced electromotive force (Emf) is calculated using the formula ε = IR, resulting in ε = 0.001217 V. The relationship between the magnetic flux and the rate of change of the magnetic field is established through the equation dΦ/dt = dB/dt, highlighting the importance of using the correct dimensions in calculations.

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PhysicsInNJ
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Homework Statement


A uniform magnetic field
Barrowitalic.gif
is perpendicular to the plane of a circular loop of diameter 18 cm formed from wire of diameter5.0 mm and resistivity 1.69 ✕ 10−8 Ω · m. At what rate must the magnitude of
Barrowitalic.gif
change to induce a 10 A current in the loop

Homework Equations


Φ = ∫ B ⋅ dA (in vector form)
φ= BA
ε= -dΦ/dt
ε=IR
R= ρL/A

The Attempt at a Solution


Current is given, so I fould the Emf using ε=IR
ε= (10) x ((1.69E-8)(2π⋅0.09))/(π⋅0.0052)) = 0.001217

Then using the value obtained for ε,
0.001217 = dΦ/dt
Φ= BA

0.001217⋅A = dB/dt

wouldn't dB/dT be the rate that B is changing?
 
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PhysicsInNJ said:
wouldn't dB/dT be the rate that B is changing?
It is, but the units are not Ampere. In general, working with units helps to find most errors.
Be careful with diameter and radius of the wire.
 
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Oh I see, my mistake was actually I used diameter instead of radius. Thank you!
 

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