Magnitude of momentum of electrons

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SUMMARY

The magnitude of momentum of electrons in a 1-meter copper wire carrying a current of 16 amperes is calculated to be 91e-12 kg m/s. This conclusion is derived from the relationship between current, charge density, and the number of electrons in motion. The calculation involves converting amperes to the number of electrons per second and using the mass of an electron (9.1e-31 kg) to find the momentum. The charge density of copper is noted as 13.6 x 10^9 Coul/m^3, which is essential for understanding the flow of electrons in the wire.

PREREQUISITES
  • Understanding of electric current and its relation to charge (16 A = 16 C/s)
  • Knowledge of electron mass (9.1e-31 kg)
  • Familiarity with charge density concepts (13.6 x 10^9 Coul/m^3 for copper)
  • Basic grasp of momentum calculation (momentum = mass x velocity)
NEXT STEPS
  • Research the derivation of momentum in conductive materials using symbolic representation.
  • Study the relationship between current density (J) and charge density (rho) in conductors.
  • Explore the effects of varying cross-sectional areas on electron flow in wires.
  • Investigate the implications of charge density on the conductivity of different materials.
USEFUL FOR

Students in physics, electrical engineers, and anyone studying the behavior of electrons in conductive materials will benefit from this discussion.

sanalsprasad
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Homework Statement


Find the magnitude of momentum of electrons in a straight wire of copper of length 1 meter carrtying a current of 16 ampere.

a) 14.56e-12 kg m/s
b) 29.12e-12 kg m/s
c) 18.2e-11 kg m/s
d) 91e-12 kg m/s

The answer is (d)

Homework Equations




The Attempt at a Solution



16 A = 16C/s
16 A = 16 * ( 6e+18 ) electrons/s [ 1 C = 6e+18 electrons ]
= 96e+18.

mass of 96e+18 electrons/s = 9.1e-31 * 96e+18
= 8.73e-11 kg/s

Since the only unit left is meter and there is only quantity of meter(1 meter), i just multiply it to make the unit of momentum.

so i get the answer as 8.73e-11 kg m/s, which is the closest to the right answer.

But this doesn't really seem to make sense, isn't there some other way? The value for mass of an electron is also not given in our textbook.

 
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The number of electrons in motion depends upon the charge density and volume of the material. In this case it's a copper wire, with charge density of 13.6 x 10^9 Coul/m^3.

I would suggest first making a derivation of the momentum purely symbolically, with an assumed cross sectional area for the wire, to being with. The area should drop out of the final expression, leaving a particularly simple result.

Things you'll need to know:

Charge density of copper (rho)
Charge on the electron.
Mass of the electron.
Formula for the current density, J = rho*v
 

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