Mann-Whitney U Test: p=1.0 - Should I Report z = 0.0001?

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Discussion Overview

The discussion revolves around the interpretation of results from a Mann-Whitney U test, specifically addressing the implications of obtaining a z-score of 0 and a p-value of 1.0. Participants explore the reporting of these results, the handling of data in SPSS, and the potential issues arising from differing participant numbers in conditions.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant questions whether to report z = 0.0001 and p = 0.99 instead of z = 0 and p = 1.0, suggesting that a z-score of 0 is impossible.
  • Another participant expresses doubt that SPSS corrects for unequal sample sizes and suggests checking data entry methods in SPSS.
  • A participant reflects on their past data entry in SPSS and considers that the software may have misinterpreted their results, leading to a reported z-score of 0.
  • Concerns are raised about the rounding of data affecting the reported p-value, with a suggestion that SPSS uses a significance threshold that could influence results.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct approach to reporting the results or the functionality of SPSS regarding unequal sample sizes. Multiple competing views remain regarding the interpretation of the z-score and p-value.

Contextual Notes

Participants mention potential issues with data entry in SPSS and the impact of rounding on statistical results. There are unresolved questions about the accuracy of the reported z-score and p-value.

nobahar
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Hey everyone,
I got z = 0, and therefore p = 1.0 in a Mann-Whitney U test. Considering this is impossible, should I instead report z = 0.0001 and p = 0.99?
Also, I have a different number of participants in my two conditions, I ran a parametric independent samples t-test, does anyone know if SPSS (the program I used) corrects for this?
Thanks in advance.
 
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I don't think SPSS sorts for that.

How have you entered your data in SPSS, since that might sometimes do the trick. You might just have entered it the wrong way. Try to transpose your data and see what SPSS then comes up with if you do the same...
 
Thanks for the reply sander.
I can’t remember how I entered it into SPSS as it was awhile ago now. I 'remember' (for what episodic memory is worth!) making several attempts. I normally do. I also did the calculations by hand (as was standard unless there was a lot of participants, in which case its far to laborious and more prone to errors). If I recall, it came close to z=0, but wasn't quite so; would this make sense? I'm pretty sure SPSS simply took it to be z=0, when it clearly couldn't have been.
I think I resolved to put P=0.99 on the assignment.
 
nobahar said:
Thanks for the reply sander.
I can’t remember how I entered it into SPSS as it was awhile ago now. I 'remember' (for what episodic memory is worth!) making several attempts. I normally do. I also did the calculations by hand (as was standard unless there was a lot of participants, in which case its far to laborious and more prone to errors). If I recall, it came close to z=0, but wasn't quite so; would this make sense? I'm pretty sure SPSS simply took it to be z=0, when it clearly couldn't have been.
I think I resolved to put P=0.99 on the assignment.

Hmmm now that's odd. SPSS is some weird stuff, it works just totally against your instincts.

I think resolving the problem by saying p=0.99 doesn't solve the problem...

It might be that your data is rounded, which might just make the difference between 0.99 and 1.00. SPSS usually uses 2.2 significance. (ie 12.34 -> 12.3456 will become 1.36).
 

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