MHB Man's Age Now: Find Out His Digit Sum Born Year

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The man was born in 1991, making him 20 years old in 2011, as the digit sum of his birth year equals his age. By 2015, he would be 24 years old. The discussion centers on the relationship between his age and the digit sum of his birth year. The calculation demonstrates a unique numerical coincidence. Therefore, as of 2015, he is 24 years old.
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A man found (at year 2011) his age at that time was all the digit sum of the year when he was born,
can you tell me ,how old is he now ?
 
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Albert said:
A man found (at year 2011) his age at that time was all the digit sum of the year when he was born,
can you tell me ,how old is he now ?
[sp]The man was born in the year 1991 so that in the year 2011 his age was 1 + 9 + 9 + 1 = 20 years ...[/sp]

Kind regards

$\chi$ $\sigma$
 
the sum of digits cannot be > 28 as 3 digit number < 2011 largest sum of digits (1999) is 28
so the year is 19ab or 20cd ( digit positions)

take 19ab.
now 10 a+ b + 1+ 9 + a + b = 111
or 11a + 2b = 111 so a is odd
a = 9 , b = 1 giving 1991
a = 7 or below give b > 9 not possible

take 20cd
so 10c + d + 2 + c + d = 11
11c + 2 d = 9
c = 0 and d = fraction
so no solution
so only solution 1991 and age = 20
 
I mean how old is he now ?(year 2015)
 
Albert said:
I mean how old is he now ?(year 2015)

24 years now
 
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