Mapping the Unit Disk onto the Complex Plane: A Holomorphic Approach

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SUMMARY

The discussion centers on the possibility of mapping the unit disk holomorphically onto the complex plane. It is established that such a mapping is impossible due to Liouville's theorem, which states that a bounded entire function must be constant. The participants clarify that while the open disk can be mapped onto the complex plane in a many-to-one manner, it cannot be done continuously or holomorphically. The Cayley map is suggested as a tool for mapping the open disk onto the upper half-plane.

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Mathematicians, complex analysts, and students studying holomorphic functions and topology will benefit from this discussion.

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Is it possible to map the unit disk onto the complex plane C holomorphically?
This is not a homework question. Thank you for your help
 
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Hi there!

This is an interesting question.

The Riemannian mapping thm. actually gives a partial answer to that question - it is possible to find such a mapping, if the domain is not all of C, so the statement is seriously doubted - otherwise Riemann would have stated his thm in a more general way

However, I'll try to sketch a counter proof:

Assume that f: C -> D is holomorphic. It is evident that f is then an entire function. What is more, for all z in C it is true that |f(z)|<=1, i.e. f is bounded, because D is bounded. Now the Liouville's thm implies that f must be constant, implying the statement is incorrect.
(the Liouville's thm is that very nice tool also used for proving the Fundamental Theorem of Algebra in less that 5 lines)


regards,
marin
 
Hi Marin,
I thank you for the response, but I believe you have misread the question. I am looking for a function from D to C. Not the other way around; and, yes, otherwise Liousville's Theorem would make it impossible.

Again: Can you map the unit disk onto C?
Thanks
 
Holomorphic maps are continuous. The unit disk is compact. Continuous maps apply compact set to compact set. The complex plane is not compact. Hence, you can't map continuously (or holomorphically) D onto C.
 
quasar987 said:
Holomorphic maps are continuous. The unit disk is compact. Continuous maps apply compact set to compact set. The complex plane is not compact. Hence, you can't map continuously (or holomorphically) D onto C.

Of course he means the open disk. The disk and the plane are homeomorphic. But not conformally equivalent (as noted, by Liouville's theorem). So what about mapping the open disk onto the complex plane in a many-to-one manner?
 
For some reason I didn't even consider that the OP might mean the open disk!
 
Thank you both of you. I retrospect, I should have made it clearer by saying the open disk.

And, yes, following the suggestion from Edgar
I can use (z-i)^2 to map the upper falf plane onto C and

Cayley map to map the open disk onto the upper half plane. I believe this will do it. Thsnk you again.
 

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