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pvpkillerx
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A particle with a mass of 0.210kg is attached to a horizontal spring with a force constant of 0.84 N/m. At the moment t=0, the particle has its maximum speed of 5m/s and is moving to the left. (Assume that the positive direction is to the right.)
Determine the particle's equation of motion, specifying its position as a function of time (use the following as necessary: t)
F = -kx
F = ma
What I did was:
-0.84x = 0.210a
-0.84x = 0.210[(v - 5)/t)]
-0.84x = 0.210[(x/t - 5)/t]
I still can't isolate for x, and i don't know if what i am doing is right. Please help.
Determine the particle's equation of motion, specifying its position as a function of time (use the following as necessary: t)
F = -kx
F = ma
What I did was:
-0.84x = 0.210a
-0.84x = 0.210[(v - 5)/t)]
-0.84x = 0.210[(x/t - 5)/t]
I still can't isolate for x, and i don't know if what i am doing is right. Please help.