• Support PF! Buy your school textbooks, materials and every day products via PF Here!

Mass attached to a horizontal spring

  • Thread starter pvpkillerx
  • Start date
A particle with a mass of 0.210kg is attached to a horizontal spring with a force constant of 0.84 N/m. At the moment t=0, the particle has its maximum speed of 5m/s and is moving to the left. (Assume that the positive direction is to the right.)

Determine the particle's equation of motion, specifying its position as a function of time (use the following as necessary: t)

F = -kx
F = ma




What I did was:
-0.84x = 0.210a
-0.84x = 0.210[(v - 5)/t)]
-0.84x = 0.210[(x/t - 5)/t]


I still can't isolate for x, and i dont know if what i am doing is right. Please help.
 
nvm, i figured it out, its 5/2Sin(2t+pi)
 

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top