- #1

- 22

- 0

**A particle with a mass of 0.210kg is attached to a horizontal spring with a force constant of 0.84 N/m. At the moment t=0, the particle has its maximum speed of 5m/s and is moving to the left. (Assume that the positive direction is to the right.)**

Determine the particle's equation of motion, specifying its position as a function of time (use the following as necessary: t)

**F = -kx**

F = ma

F = ma

**What I did was:**

-0.84x = 0.210a

-0.84x = 0.210[(v - 5)/t)]

-0.84x = 0.210[(x/t - 5)/t]

-0.84x = 0.210a

-0.84x = 0.210[(v - 5)/t)]

-0.84x = 0.210[(x/t - 5)/t]

I still can't isolate for x, and i don't know if what i am doing is right. Please help.