I Mass Dimension of Fields (Momentum space)

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The mass dimension of a scalar field ##\phi## is established as ##\frac{d-2}{2}## in d-dimensional space-time. The discussion explores the mass dimension of the field in momentum space, ##\phi(p)##, particularly in the context of the two-point correlation function. It is noted that the Dirac delta function contributes a mass dimension of ##-d##, while the fractional component contributes ##-2##. Consequently, the overall mass dimension of ##\phi(p)## is determined to be ##\frac{-d-2}{2}##. This conclusion is reached through the Fourier transform and the action expressed in momentum variables.
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Hi all,
We know from requiring the action be invariant that the mass-dimension of a scalar field ##\phi## is ##\frac{d-2}{2}## where ##d## is the space-time dimension. But what is the mass-dimension of ##\phi(p)##? I ask because free-theory 2-pt correlation function (in Euclidean space) is written as ##\langle\phi(p)\phi(q)\rangle = (2\pi)^{d}\delta^{d}(p+q)\frac{1}{p^{2}+m^{2}}##. The dirac delta seems to contribute a mass dimension ##-d## and then the fractional component contributes another mass-dimension of ##-2##? I'm not sure if this makes sense.

Thanks.
 
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Indeed, and therefore …

Another way of deriving it is to look at the action expressed in the momentum variables or just the definition of ##\phi(p)## in terms of ##\phi(x)##.
 
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Orodruin said:
Indeed, and therefore …

Another way of deriving it is to look at the action expressed in the momentum variables or just the definition of ##\phi(p)## in terms of ##\phi(x)##.
Ah, so the mass dimension is ##\frac{-d-2}{2}##. The fourier transform is indeed significantly simpler to see this.
 
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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