Math Olympiad Problem: Proving a+b+c=d with 69 Distinct Integers between 1-100

Click For Summary
SUMMARY

The discussion centers on proving that within a set of 69 distinct positive integers between 1 and 100, it is always possible to select four integers a, b, c, and d such that a + b + c = d. The proof utilizes the pigeonhole principle, where the smallest integer is designated as a and the largest as d. By analyzing the number of possible pairs for b and c within the constraints of the set, participants concluded that the relationship holds true. The discussion also highlights the enjoyment of mathematical proofs, particularly those involving combinatorial principles.

PREREQUISITES
  • Pigeonhole principle
  • Basic combinatorial mathematics
  • Understanding of distinct integers
  • Familiarity with mathematical proofs
NEXT STEPS
  • Study the pigeonhole principle in depth
  • Explore combinatorial proofs in mathematics
  • Investigate the properties of distinct integers in number theory
  • Read "Problem Solving" by Larson for advanced proof techniques
USEFUL FOR

Mathematics enthusiasts, educators, and students interested in combinatorial proofs and the application of the pigeonhole principle in problem-solving scenarios.

tongos
Messages
84
Reaction score
0
i have 69 distinct positive whole numbers between 1 and 100. i pick out 4 integers a,b,c,d. prove that i can always pick out 4 integers such that a+b+c=d. can this always hold true with 68 positive integers?
 
Mathematics news on Phys.org
i'm assuming that you don't have to pick out a+b+c=d all the time but there exists a quadruple in your set of 69.

The proof relies on the pigeon hole principle:
[1]let a and d be the smallest and largest of your set of 69 respectively.
[2]find the number of pairs taht b & c can be within 1-100 and the set of 69.
[3]Compare these two values.
 
thanks! I seem to know what to do now. The fun part about this problem is the pigeon hole principle. I love math problems like this one.
one of my favorite math problems (though simple) is this:
Prove that at any party, two friends at that party must have the same amount of friends present there (given ofcourse that if someone is a friend to you, you are friend to that someone).
 
if you need a good book to further your proving skillz pick up
"problem solving" by Larson.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
29K
  • · Replies 66 ·
3
Replies
66
Views
7K