Mathematica - what is wrong with ImplicitRegion[]

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In summary, the integral given is: $$\int_S z\,dS$$ where S is the lateral (surface) area of the cylinder $y^2+z^2=4$ cut off by two planes, $x=y-3$ and $x=6-z$. Using the parametrization $r(x,\theta)=(x,2\cos(\theta), 2\sin(\theta))$, the integral can be simplified to $-8\pi$. However, when using Mathematica, the result given is $8\pi$, which is due to a bug in the software. No further ideas or solutions have been found.
  • #1
PrecPoint
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TL;DR Summary
Trying to understand how to use an implicit region in Integrate.
I'm working the integral
$$\displaystyle \int_S z\,dS$$

Where [itex]S[/itex] is the lateral (surface) area of the cylinder [itex]y^2+z^2=4[/itex] cut off by two planes, [itex]x=y-3[/itex] and [itex]x=6-z[/itex].

Using the parametrization [itex]r(x,\theta)=(x,2\cos(\theta), 2\sin(\theta))[/itex] this is pretty straight forward

$$\int 2\sin(\theta)|\frac{\partial r}{\partial x}\times\frac{\partial r}{\partial \theta}|\,dxd\theta=-8\pi$$

However, when I use Mathematica I get the following:

Code:
myReg2 = ImplicitRegion[y^2 + z^2 == 4, {{x, y - 3, 6 - z}, y, z}];
Integrate[z, {x, y, z} \[Element] myReg2]

>8 \[Pi]

Even using my exact parametrization:

Code:
myRegion = 
  ParametricRegion[{x, 2*Cos[\[Theta]], 
    2*Sin[\[Theta]]}, {{x, 2*Cos[\[Theta]] - 3, 
     6 - 2*Sin[\[Theta]]}, {\[Theta], 0, 2 \[Pi]}}];
Integrate[z, {x, y, z} \[Element] myRegion]

>8 \[Pi]

Obviously I'm missing something, but I can't figure it out and it drives me nuts. Any ideas would be welcome!
 
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  • #2
Quick update*; so I was not missing something. Apparently, this is a bug in Mathematica.
 
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