Matrix Problem: Find A and B such that A = O, B =O, AB= O and BA =O

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Homework Help Overview

The discussion revolves around finding two matrices A and B that are not null matrices, yet satisfy the conditions AB = 0 and BA ≠ 0. Participants explore the properties of matrices, particularly focusing on singular and nilpotent matrices.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the structure of matrices A and B, considering triangular forms and other types. Questions arise regarding the necessity of both matrices being square and the implications of the conditions given. Some suggest specific entries for A and B to satisfy the equations.

Discussion Status

The discussion is active, with various approaches being suggested, including the use of triangular matrices and specific entries. There is no explicit consensus, but participants are engaging with the problem and exploring different interpretations and methods.

Contextual Notes

Participants note the constraints of the problem, such as the requirement for A and B to be non-null while still satisfying the matrix multiplication conditions. There is uncertainty regarding the implications of the conditions on the properties of the matrices involved.

Crystal037
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Homework Statement
Find a matrix such that A and B such that A not equal to null matrix B not equal to null matrix AB= null matrix and BA not equal to null matrix
Relevant Equations
A! = O, B! =O, AB= O and BA! =O
Let
A=
[ a b]
[ c d ]
B =
[ w x]
[ y z]
Then aw +by=0 bx+dz=0
cw+dy=0 cx+dz=0
aw+cx! =0 bw+x! =0
ya+cz!=0 by+dz! =0
But I don't get the answer after this
 
Last edited:
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Crystal037 said:
Problem Statement: Find a matrix such that A and B such that A not equal to null matrix B not equal to null matrix AB= null matrix and BA not equal to null matrix
I'm not sure I follow your problem statement. Do ##A## and ##B## both need to be square? The fact that ##BA \neq \mathbf 0## implies that ##A## and ##B## are both non-zero.

The way to think about this is both matrices are singular. You'll want at least one to be nilpotent... in either case they both have 'a lot' of zero eigenvalues. What's the simplest way to come up with an example fitting that? Make both of them triangular matrices

edit:
another approach would be to select a mix of other 'easy' matrices -- perhaps a symmetric rank one matrix, and full rank diagonal matrix... playing around with triangular matrices is probably easier though.
 
Last edited:
Crystal037 said:
Problem Statement: Find a matrix such that A and B such that A not equal to null matrix B not equal to null matrix AB= null matrix and BA not equal to null matrix
Relevant Equations: A! = O, B! =O, AB= O and BA! =O

Let
A=
[ a b]
[ c d ]
B =
[ w x]
[ y z]
Then aw +by=0 bx+dz=0
cw+dy=0 cx+dz=0
aw+cx! =0 bw+x! =0
ya+cz!=0 by+dz! =0
But I don't get the answer after this
Pick ##a,\ b,\, w,\, y## such that ##aw = -by## and have all other entries be zero.
 
The matrix multiplies seem wrong. I'm thinking:

$$AB = \begin{bmatrix} aw+by & ax+bz \\ cw+dy & cx+dz \end{bmatrix} = 0$$
$$BA = \begin{bmatrix} aw+cx & bw+dx \\ ay+cz & by+dz \end{bmatrix} \neq 0$$
 
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It certainly is possible.

Here's a screen shot from a Ti-84 graphics calculator.

244085


Of course, that does not give the entries for the matrices, but I pretty much followed the advice in Post #3 in constructing them..
 
Last edited:

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