Matter to Energy: Kinetic + Rest Mass?

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Discussion Overview

The discussion revolves around the energy released during the decay of a moving particle, specifically whether this energy is equal to the rest mass plus kinetic energy or just the rest mass. The scope includes theoretical considerations of energy conservation, relativistic effects, and the implications of particle decay.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • Some participants propose that the energy released during decay must equal both the rest energy and the kinetic energy of the original particle.
  • Others argue that the Law of Conservation of Energy applies, stating that energy before decay equals energy after decay.
  • A participant questions whether relativistic energy should be considered instead of just rest energy, suggesting that acceleration affects mass and energy calculations.
  • Another participant emphasizes the need for clarity in the original question, noting the lack of information about the particle's speed and the nature of the decay products.
  • Several participants introduce equations related to both Newtonian and relativistic frameworks to illustrate their points about energy conservation before and after decay.
  • One participant highlights the importance of specificity in physics discussions, suggesting that the question posed was not clear enough.
  • Another participant reiterates that total energy (mass energy plus kinetic energy) of the decay products equals the total energy of the reactants, emphasizing conservation of both energy and momentum.

Areas of Agreement / Disagreement

Participants do not reach consensus on whether the energy released is simply the rest mass or includes kinetic energy. Multiple competing views remain regarding the application of relativistic versus classical mechanics in this context.

Contextual Notes

There are limitations in the discussion, including assumptions about the particle's speed and the nature of the decay products, as well as unresolved mathematical steps in the proposed equations.

Shark 774
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If a particle is moving at some particular speed and then suddenly decays, is the energy released equal to the rest mass of the particle plus the kinetic energy it had before decay, or simply its rest mass??

Thanks.
 
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It has to equal both the rest energy and the kinetic energy that the original particle had.
 
The "Law of Conservation of Energy" must be applied here.

Energy Before Decay = Energy After Decay
 
Sup_Principia said:
The "Law of Conservation of Energy" must be applied here.

Energy Before Decay = Energy After Decay

Correct me if am wrong but is it correct. i thought the merely acceleration of the object should account for a change in mass hence relativistic energy is considered. Shouldn't it be the relativistic energy instead of the rest energy..
 
Ikoro said:
Correct me if am wrong but is it correct. i thought the merely acceleration of the object should account for a change in mass hence relativistic energy is considered. Shouldn't it be the relativistic energy instead of the rest energy..

In the original post (OP) there was no mention of how fast the "Mass" particle was moving.

Shark 774 said:
If a particle is moving at some particular speed and then suddenly decays, is the energy released equal to the rest mass of the particle plus the kinetic energy it had before decay, or simply its rest mass??

I assumed non-relativistic speed because it was not mentioned! In Shark's question the "Moving Mass" particle decays. He does not say whether the decay object is a "Photon" or another separate "Mass" unit.

In either case the Conservation of energy applies.

Inertial Mass --- Inertial Mass
Energy Before Decay = Energy After Decay

\frac{1}{2} m_{Net}{v^2_{Original}} = \frac{1}{2} m_{New}{v^2_{New}} + \frac{1}{2} m_{Decay}{v^2_{Decay}}

Inertial Mass --- Photon
Energy Before Decay = Energy After Decay

\frac{1}{2} m_{Net}{v^2_{Original}} = \frac{1}{2} m_{New}{v^2_{New}} + h_{Planck}f_{frequency}

If the above does not address the post, then either Ikoro or Shark needs to be a bit clearer!
 
Sup_Principia said:
Inertial Mass --- Photon
Energy Before Decay = Energy After Decay

\frac{1}{2} m_{Net}{v^2_{Original}} = \frac{1}{2} m_{New}{v^2_{New}} + h_{Planck}f_{frequency}

If the above does not address the post, then either Ikoro or Shark needs to be a bit clearer!

Being a relativity forum, relativistic equations rather than Newtonian equations may be more appropriate so:

Inertial Mass --- Photon
Total Energy Before Decay = Total Energy After Decay

\frac{M c^2}{\sqrt{1-v^2/c^2}} = \frac{M_{final} c^2}{\sqrt{1-v_{final}^2/c^2}} + hf

Just for info:

M is the rest mass and the original kinetic energy is:

\frac{M c^2}{\sqrt{1-v^2/c^2}} - M c^2
 
Last edited:
yuiop said:
Being a relativity forum, relativistic equations rather than Newtonian equations may be more appropriate so:

Inertial Mass --- Photon
Total Energy Before Decay = Total Energy After Decay

\frac{M c^2}{\sqrt{1-v^2/c^2}} = \frac{M_{final} c^2}{\sqrt{1-v_{final}^2/c^2}} + hf

Just for info:

M is the rest mass and the original kinetic energy is:

\frac{M c^2}{\sqrt{1-v^2/c^2}} - M c^2

Thanks for your response, that clears it up. You're right, this is a relativity forum and hence people may need to use a little more common sense, rather than others needing to be clearer.
 
yuiop said:
Being a relativity forum, relativistic equations rather than Newtonian equations may be more appropriate so:


Shark 774 said:
Thanks for your response, that clears it up. You're right, this is a relativity forum and hence people may need to use a little more common sense, rather than others needing to be clearer.


First and foremost; Physics is an exact science, and words do matter. This is like saying, "Is that a soda?" When you really intended to say "Is that a "Coke 'a' Cola!"

Second; one of the main tenents of "Special Relativity" is the knowledge of the photon and its speed of light motion relative to matter. And this was why I added both equations, one that was relativistic at low speeds, and one that involved classical relativity.

Third; I answered you question, in a way that was to reveal how much "non-sense" was in your question. Or said in a nice way, to reveal that your question was not posed as clear as it should have been!

We are not in the 1800's anymore, in the 21st Century there is so much physics we

yuiop said:
Inertial Mass --- Photon
Total Energy Before Decay = Total Energy After Decay

\frac{M c^2}{\sqrt{1-v^2/c^2}} = \frac{M_{final} c^2}{\sqrt{1-v_{final}^2/c^2}} + hf

Just for info:

M is the rest mass and the original kinetic energy is:

\frac{M c^2}{\sqrt{1-v^2/c^2}} - M c^2


Maybe yuiop, Shark are not use to being specific; but the above equation is a bit more special relativity specific, using the following equations.


Rest Mass
m_{Net_0}

Relativistic Mass Before Decay
\frac{m_{Net_0}}{\sqrt{1-v^2_{Initial}/c^2_{Light}}}

Mass due to relativistic motion that is added to the Rest Mass Before Decay
\Delta m_{Motion} = \frac{m_{Net_0}}{\sqrt{1-v^2_{Initial}/c^2_{Light}}} - m_{Net_0}

Relativistic Doppler Frequency Observed
f_{Observed} = f_{Souce} \sqrt{\frac{1 - \frac{v_{final}}{c_{Light}}}{1 + \frac{v_{final}}{c_{Light}}}}


Inertial Mass --- Photon
Total Energy Before Decay = Total Energy After Decay

\frac{m_{Net_0}c^2_{Light}}{\sqrt{1-v^2_{Initial}/c^2_{Light}}} = \frac{m_{Net_0}c^2_{Light}}{\sqrt{1-v^2_{Final}/c^2_{Light}}} + h_{Planck}f_{Observed}

m_{Net_0}c^2_{Light} + \Delta m_{Motion}c^2_{Light} = \frac{m_{Net_0}c^2_{Light}}{\sqrt{1-v^2_{Final}/c^2_{Light}}} + (h_{Planck}f_{Souce}) \sqrt{\frac{1 - \frac{v_{final}}{c_{Light}}}{1 + \frac{v_{final}}{c_{Light}}}}

Hopefully this is relativistic enough for you!
 
Shark 774 said:
If a particle is moving at some particular speed and then suddenly decays, is the energy released equal to the rest mass of the particle plus the kinetic energy it had before decay, or simply its rest mass??
The total energy (mass energy + kinetic energy) of the decay products is equal to the total energy of the reactants. Total energy is conserved. The total momentum is also conserved.
 

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