Max aircraft range - electric powered

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SUMMARY

The maximum range of electric-powered RC aircraft is determined by the equation R = (C/g) x fbatt x ε x (L/D), where C is the battery energy capacity, g is gravity, fbatt is the battery mass fraction, ε is propulsion efficiency, and L/D is the lift-to-drag ratio. Using lithium-ion batteries with a specific energy of approximately 1 MJ/kg, the fundamental range for such aircraft is calculated to be 100 km (62 miles). With optimal design parameters, including a glide ratio of 37 and a battery mass fraction of 0.6, the maximum range can extend to 1780 km (1100 miles). Future advancements in battery technology, such as lithium-sulfur batteries, could further increase this range to 1390 miles.

PREREQUISITES
  • Understanding of the Breguet range equation for aircraft
  • Knowledge of propulsion efficiency metrics
  • Familiarity with lift-to-drag ratio concepts
  • Basic principles of battery energy density
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Aerospace engineers, RC aircraft designers, battery technology researchers, and anyone interested in optimizing electric aircraft range and performance.

mheslep
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I'm trying to come up with some ballpark ranges for RC electric powered aircraft. The literature I find so far on range, like the Breguet range equation, seems focused on mass change from fuel consumption which is not the case in battery powered electric aircraft. So I thought I would start from scratch for my edification and invite sanity checks. McKay's reference, here, provided guidance. Below I've substituted terms convenient for my design.

Fundamentally, the maximum range is some optimal aircraft velocity x time aloft, and time aloft is the total energy carried divided by the rate at which it is used, i.e. power, corrected for the efficiency of the propulsion system:

R = Vopt x (Ebatt/P) x ε
where:
R = maximum range
Ebatt = energy capacity of the battery
ε = propulsion efficiency
P = power​

and since force is power / velocity:

R = (Ebatt/Fthrust) ε
for level flight:

Fthrust = Drag
Lift = mg

or

Fthrust = mg (D/L)​

where:
m = aircraft mass
g = gravity
L/D = well known lift to drag ratio, or the glide ratio.​

then
R = Ebatt x ε x (L/D) / mg
Ebatt = Cbatt x me
where:
Cbatt = battery specific energy
me = mass of battery​

let
fbatt = fraction of aircraft mass dedicated to the battery
and
me = fbatt m​

then
R = Cbatt x fbatt x m x ε x (L/D) / (mg)
finally:
R = ( Cbatt/g ) x fbatt x ε x (L/D)

The term fbatt x ε x (L/D) is dimensionless. The fundamental range dependent on just carried energy is C/g.

Next up, some numbers.
 
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Li Ion batteries are just short of 1 megajoule per kg, so in SI units C=1e6, g=10, the 'fundamental' range of a Li Ion powered aircraft is C/g = 100 km (62 miles). That applies to any aircraft so powered, of any size and air frame BTW.

Now for the dimensionless bit, the parameters.

Propulsion efficiency:
ε = ηbatt x ηfan x ηemotor

Common efficiencies for the battery and the motor are ~93%. If a prop maxes out at 85%, I'm guessing a duct-ed fan w/ vanes can also hit 93%, making the overall efficiency a convenient ε=0.8

Glide Ratio:
Best powered aircraft glide ratio to my knowledge is the Virgin Atlantic Global flyer. The Flyer achieved an L/D = 37.

Battery mass fraction:
I don't know. Commercial aircraft like a 747 top off with f=0.5. I'm guessing I can stuff f=0.6 in the airframe.

This RC 'Global Flyer' design gives a multiplier of fbatt x ε x (L/D) = 17.8
so Rmax li-ion = 1780 km (1100 miles)
 
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I have some literature on electric ducted fans that I think gives some expressions for range and endurance, but I don't have it with me right now.
 
Buy a blimp covered in flexible photo-voltaic materials.

(sorry. just had to subscribe to my favorite topic. :redface:)
 
I note 1 MJ/kg takes the electric Flyer from New York to Bermuda (774 miles). Lithium Sulfur has demonstrated 1.26 MJ/kg, which would extend Rmax to 1390 miles. Still wont' cross the Atlantic (Newfoundland to Scotland) at 1900 miles
 
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Ah, a Lithium primary battery (no recharge) Li thionyl chloride goes to 1.8MJ => 1980 miles. Primary batteries are often low power density though.
 
jhae2.718 said:
I have some literature on electric ducted fans that I think gives some expressions for range and endurance, but I don't have it with me right now.
Look forward to it.
 
Interestingly, I see an RC 'model' aircraft (i.e. less than 11 pounds) crossed the Atlantic for the first time in 2003, using 2.2 kg of fuel (Coleman stove fuel).

http://en.wikipedia.org/wiki/The_Spirit_of_Butts_Farm
220px-Tam5.jpg
 
I see the glide ratio of some modern jets is 20:1. So to build an electric regional jet w legs of a 1000 mi (1700km), battery energy density needs to improve less than 2X, to 1.8 mj/kg: R=180km * .8 * .5 * 20. That is, as soon as an e motor comes along w the same specific power of a gas turbine fan engine (7kw/kg).
 
  • #10
mheslep said:
Look forward to it.

I was mistaken, it doesn't have anything on range. There are some equations for static thrust, power required, though. Let me know if you want those.

The booklet is from 1977, and is "Ducted Fans for Light Aircraft" by R.W. Hovey.
 
  • #11
jhae2.718 said:
I was mistaken, it doesn't have anything on range. There are some equations for static thrust, power required, though. Let me know if you want those.

The booklet is from 1977, and is "Ducted Fans for Light Aircraft" by R.W. Hovey.
Thanks. That reference led me to another which cites Hovey.

http://books.google.com/books?id=Yc...ns for Light Aircraft" by R.W. Hovey.&f=false

By Piolenc and Vwright. They walk through a ducted fan design example which has duct efficiency at 0.9, fan efficiency at 0.9, for a total of 0.81, i.e. less than a prop at its best?
 

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