MHB Max and min line equation

  • Thread starter Thread starter leprofece
  • Start date Start date
  • Tags Tags
    Line Max
Click For Summary
The discussion focuses on finding the equation of a straight line through a fixed point P(a, b) in the first quadrant that minimizes the segment length intersecting the positive axes. The equation derived is y - b = m(x - a), where m is the slope. To determine m, the x and y intercepts of the line are calculated, leading to a quartic equation involving m. The solution reveals that m = -√[3]{b/a} is a root, indicating the optimal slope for the line. The segment length can be expressed as L2/3 = a2/3 + b2/3, providing a concise formula for further calculations.
leprofece
Messages
239
Reaction score
0
1) If P (a, b) is a fixed point located in the first quadrant. Find the equation of the straight line which, passing through P, is such that the length of the segment that on it limits the semiaxes positives is minimal. Calculate the segment lenght

Answers
y-b = Cubic sqrt ((b)/a) (x-a)

L2/3 = a2/3 + b 2/3

Equation y-b = m(x-a)
According to the answer I must get the slope m derivating what?
 
Physics news on Phys.org
Determine the $x$ and $y$ intercepts of the line, then find the square of the line segment as a function of $m$ using the Pythagorean theorem. Differentiating it produces an expression containing $m$, $1/m^2$ and $1/m^3$, i.e., essentially a quartic equation. It may be tricky to solve it, but it is easy to verify that $m=-\sqrt[3]{\dfrac{b}{a}}$ is root.
 
Thread 'Problem with calculating projections of curl using rotation of contour'
Hello! I tried to calculate projections of curl using rotation of coordinate system but I encountered with following problem. Given: ##rot_xA=\frac{\partial A_z}{\partial y}-\frac{\partial A_y}{\partial z}=0## ##rot_yA=\frac{\partial A_x}{\partial z}-\frac{\partial A_z}{\partial x}=1## ##rot_zA=\frac{\partial A_y}{\partial x}-\frac{\partial A_x}{\partial y}=0## I rotated ##yz##-plane of this coordinate system by an angle ##45## degrees about ##x##-axis and used rotation matrix to...

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K