Max and min line equation

  • Context: MHB 
  • Thread starter Thread starter leprofece
  • Start date Start date
  • Tags Tags
    Line Max
Click For Summary
SUMMARY

The discussion focuses on deriving the equation of a straight line that minimizes the segment length intersecting the positive axes from a fixed point P(a, b) in the first quadrant. The equation is given as y - b = Cubic sqrt(b/a) (x - a), with the segment length expressed as L^(2/3) = a^(2/3) + b^(2/3). The slope m is determined through differentiation, leading to a quartic equation that confirms m = -sqrt[3]{b/a} as a root.

PREREQUISITES
  • Understanding of coordinate geometry and straight line equations
  • Familiarity with calculus, specifically differentiation
  • Knowledge of the Pythagorean theorem
  • Basic algebra for solving quartic equations
NEXT STEPS
  • Study the derivation of cubic functions and their properties
  • Learn about optimization techniques in calculus
  • Explore the application of the Pythagorean theorem in coordinate geometry
  • Research methods for solving quartic equations
USEFUL FOR

Mathematicians, engineering students, and anyone interested in optimization problems in geometry.

leprofece
Messages
239
Reaction score
0
1) If P (a, b) is a fixed point located in the first quadrant. Find the equation of the straight line which, passing through P, is such that the length of the segment that on it limits the semiaxes positives is minimal. Calculate the segment lenght

Answers
y-b = Cubic sqrt ((b)/a) (x-a)

L2/3 = a2/3 + b 2/3

Equation y-b = m(x-a)
According to the answer I must get the slope m derivating what?
 
Physics news on Phys.org
Determine the $x$ and $y$ intercepts of the line, then find the square of the line segment as a function of $m$ using the Pythagorean theorem. Differentiating it produces an expression containing $m$, $1/m^2$ and $1/m^3$, i.e., essentially a quartic equation. It may be tricky to solve it, but it is easy to verify that $m=-\sqrt[3]{\dfrac{b}{a}}$ is root.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K