Max Load for Beach Mattress on Dead Sea Surface: 142.8 kg

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SUMMARY

The maximum load a beach mattress can carry on the surface of the Dead Sea is 142.8 kg. This calculation is based on the mattress's volume of 120 L and its mass of 6.0 kg, combined with the density of the saline water at 1240 kg/m³. The buoyant force, calculated using the formula Wwater displaced = density * volume * gravity, results in a buoyant force of 1459.728 N. The load capacity is determined by subtracting the weight of the mattress from the buoyant force.

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Homework Statement


A beach mattress filled with air has a volume of 120 L and a mass of 6.0 kg. The saline
water of the Dead Sea has a density of 1240 kg/m3. Assume that the mattress retains its
shape and volume regardless of load.

Homework Equations


What is the maximum load the mattress can carry on the surface of the Dead Sea?

The Attempt at a Solution


Wwater displaced = 1240*0.12*9.81 = 1459.728 N and that's the buoyancy force ''buoyant force'' Fb

Fb=Wmattress+Wload
Wload=Fb-Wmattress
mload*g=Fb-mmattress*g
mload=(Fb-mmattress*g)/g
mload=(1459.728-6*9.81)/9.81
mload=142.8 Kg
 
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It looks good.

Note: mload = (1459.728-6*9.81)/9.81 = (1240*0.120*9.81-6*9.81)/9.81 = (1240*0.120-6) = 142.8 kg
 
Last edited:

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