Maximize Volume of Right Circular Cone with Constant Slant Edge

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To maximize the volume of a right circular cone with a constant slant edge of 6 cm, the relationship between the height and radius must be established. The volume V of the cone can be expressed in terms of the slant edge length x, leading to the formula V = (1/3)πr²h. By applying calculus, the maximum volume occurs when the height is determined to be 4.8 cm, resulting in a maximum volume of approximately 48π cm³. This analysis highlights the geometric relationships and optimization techniques involved in maximizing the volume of a right circular cone.
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1. The slant edge of a right circular cone is 6 cm in length. Find the height of the cone when the volume is a maximum.

2. Find the maximum volume of a right circular cone whose slant edge has a constant length measure a.
 
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I would add,
3. Express the volume V(x) of a right circular cone in terms of the length x of its slant edge.

Then solve 3, then 2, then 1.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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