Maximizing Profit: Calculating Optimal Widget Sales | Widget Company

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The discussion focuses on calculating the optimal number of widgets a company must sell to achieve a profit of at least $7000, given a selling price of $49 and initial manufacturing costs of $2500 plus $32.35 per widget. The profit function derived is P(x) = -2500 + 16.65x, leading to the conclusion that 571 widgets must be sold to meet the profit goal. Additionally, if manufacturing costs increase by $2.75, the new profit function becomes P(x) = -2500 + 14x, requiring the sale of 679 widgets to achieve the same profit. The calculations have been verified as correct by forum participants.

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CanaBra
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Profit function!

Problem: A company is considering selling a new line of widgets at a special promotional price of $49. If the cost of setting up the manufacturing process is $2500, an each widget costs $32.35 to produce, how many should the company sell in order to realize a profit of at least $7000? If the cost of manufacturing increases by $2.75, how many widgets must be sold at the original selling price to obtain the same profit?

Here is what I have done:

R(x) = 49x
C(x)=$2500+$32.35x
P(x)= -2500+16.65x

If P(x) =$7000, then
7000= -2500+16.65x
7000+2500=16.65x
9500 =16.65x
9500/16.65 = x
x = 570.57...

If costs increases by $2.75, then
C(x) = 2500 + 35
P(x)-C(x) = -2500 + 14x
If P(x) = $7000, then

7000= -2500+14x
7000+2500 = 14x
9500/14 = x
x=678.57...

Can anyone double check this answer for me or tell me if I am completely lost?
Thank you in advance
 
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Looks correct to me. The equationf produces a higher result when the cost to manufacture the widget increases.

Thanks
Matt
 

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