Maximizing Vertical Height in Frictionless Rolling Motion on an Incline

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Homework Help Overview

The discussion revolves around a physics problem involving a hollow sphere rolling down an incline and transitioning to a frictionless curve. The problem focuses on determining the vertical height the sphere will reach after descending from an initial height.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conservation of energy in the context of rolling motion, questioning how the transition to a frictionless surface affects the sphere's rotation and kinetic energy. There is an exploration of whether the sphere's rotation changes upon reaching the frictionless section.

Discussion Status

The discussion includes attempts to clarify the relationship between rotational and translational kinetic energy. Some participants are actively engaging with the problem, while others are seeking to understand the implications of the sphere's motion on energy conservation.

Contextual Notes

There is a note of uncertainty regarding the effects of the frictionless transition on the sphere's rotation and energy distribution, which remains a point of exploration among participants.

John Kolby
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Homework Statement


A hollow sphere of mass M and radius R (I = 2MR2 /3) is released from rest at height h and rolls down a curved surface without slipping until it reaches the lowest point, O..

The curve to the right of O is frictionless. If the sphere continues past point O, what vertical height will it reach?
(In the diagram, the curve looks like a semi circle)

Homework Equations


KEr = 1/2 M W2
KEl = 1/2MV2

The Attempt at a Solution


According to my knowledge, if its frictionless and energy is conserved it should reach the same high.

mgh = 1/2 M W2 + 1/2MV2
**If I did something wrong I apologize, first time on this forum
 
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John Kolby said:

Homework Statement


A hollow sphere of mass M and radius R (I = 2MR2 /3) is released from rest at height h and rolls down a curved surface without slipping until it reaches the lowest point, O..

The curve to the right of O is frictionless. If the sphere continues past point O, what vertical height will it reach?
(In the diagram, the curve looks like a semi circle)

Homework Equations


KEr = 1/2 M W2
KEl = 1/2MV2

The Attempt at a Solution


According to my knowledge, if its frictionless and energy is conserved it should reach the same high.

mgh = 1/2 M W2 + 1/2MV2

**If I did something wrong I apologize, first time on this forum
Hello John Kolby. Welcome to PF !

Does the rotation of the sphere change once it gets to the frictionless part of the curve?

Does its rotation correspond to some amount of kinetic energy?
 
SammyS said:
Does the rotation of the sphere change once it gets to the frictionless part of the curve?

Does its rotation correspond to some amount of kinetic energy?
I don't think the rotation changes. The rotation accounts to Kr which I account for with 1/2MW2
 
Solved it thank you!
 

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