Maximum voltage on coaxial cable?

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SUMMARY

The maximum voltage that a coaxial cable can handle is determined by the breakdown voltage of the dielectric material and the spacing between the conductors. In this discussion, the maximum electric field is specified as E=3MV/m, with an inner radius of a=2cm and an outer radius of b=2.72a. The dielectric is described as homogeneous and linear, but the dielectric constant (εr) is not provided, which complicates the calculation of maximum charge (Qmax) and voltage (U). The relationship between the electric field and voltage is expressed through the integral U=∫E*dl.

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  • Understanding of coaxial cable geometry and dimensions
  • Familiarity with electric fields and breakdown voltage concepts
  • Knowledge of dielectric materials and their properties
  • Proficiency in calculus for evaluating integrals
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cdummie
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Homework Statement


How to determine maximum voltage that coaxial cable, whose height is L and is filled with dielectric in such way that E is the same in the dielectric and in the part of the cable that isn't filled with dielectric (only vacuum),can handle if i have maximum electric field that is E=3MV/m, and i have inner radius a=2cm and outer b=2.72a. Dielectric is homogeneous and linear.

Homework Equations

The Attempt at a Solution


I tried like this U=∫E*dl but since i know exact value of Emax and no data for εr and Qmax i can't solve this.
 
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cdummie said:

Homework Statement


How to determine maximum voltage that coaxial cable, whose height is L and is filled with dielectric in such way that E is the same in the dielectric and in the part of the cable that isn't filled with dielectric (only vacuum),can handle if i have maximum electric field that is E=3MV/m, and i have inner radius a=2cm and outer b=2.72a. Dielectric is homogeneous and linear.

Homework Equations

The Attempt at a Solution


I tried like this U=∫E*dl but since i know exact value of Emax and no data for εr and Qmax i can't solve this.

The part I bolded looks like a typo -- is it?

The breakdown voltage will depend on the breakdown voltage of the dielectric and the spacing between the conductors. If you have the maximum electric field and the separation (and the dielectric constant), you should be able to calculate the breakdown voltage.
 
Last edited:
berkeman said:
The part I bolded looks like a typo -- is it?

The breakdown voltage will depend on the breakdown voltage of the dielectric and the spacing between the conductors. If you have the maximum electric field and the separation (and the dielectric constant), you should be able to calculate the breakdown voltage.

I don't know what you mean, bolded part is correct b=2.72a, that's the given value. I don't have the value for the dielectric constant, if i had i could easily find Qmax and then find U using E expressed with Qmax. The problem is that i don't have dielectric constant.
 
cdummie said:
I don't know what you mean, bolded part is correct b=2.72a, that's the given value. I don't have the value for the dielectric constant, if i had i could easily find Qmax and then find U using E expressed with Qmax. The problem is that i don't have dielectric constant.

Oh, I see now. The outer radius is given as a multiple of the inner radius -- that's what was confusing me about the dimensions.

The rest of the question is a bit confusing as well. Is there a figure that you can post? What does it mean when it seems to say

cdummie said:
and is filled with dielectric in such way that E is the same in the dielectric and in the part of the cable that isn't filled with dielectric

That makes no sense unless the dielectric constant is the same as free space. Is the problem copied word-for-word?
 
berkeman said:
Oh, I see now. The outer radius is given as a multiple of the inner radius -- that's what was confusing me about the dimensions.

The rest of the question is a bit confusing as well. Is there a figure that you can post? What does it mean when it seems to say
That makes no sense unless the dielectric constant is the same as free space. Is the problem copied word-for-word?
It's not completely filled with dielectric, it's filled with dielectric to the some point and rest is free-space.
 

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