Power Transmitted in a Coaxial Cable

Marcus95
Messages
50
Reaction score
2

Homework Statement


A coaxial transmission line consists of an inner cylindrical conductor of radius a = 1 mm and a
cylindrical outer conductor chosen to make the characteristic impedance 75 ohm. The space
between the conductors is lled with a gas which can stand a maximum eld of 105 V/m
without dielectric breakdown. Estimate the maximum mean radio-frequency power that
can be transmitted along this line into a matching load.

Homework Equations


On transmission line
## Z = \sqrt{L/C} ##
For coaxial with radius a and b:
##C = \frac{2\pi \epsilon \epsilon_0}{ln(b/a)} ##
##L = \frac{\mu_0 ln(b/a)}{2\pi} ##

The Attempt at a Solution


The voltage between the two conductors is by Gauss's law:
## V = \int \boldsymbol{E} \cdot d\boldsymbol{r} = E_0 ln(b/a) ##
hence:
## V_{max} = E_{max} ln(b/a) ##
also:
##Z = \sqrt{\mu / \epsilon \epsilon_0} \frac{ln(b/a)}{2\pi} ##
Using ##P = VI = V^2/Z ## and asuuming ##epsilon \approx 1## gives:
##P_{max} = 0.21 GW##, but the answer is supposed to be 104 W.

What am I doing wrong? Many thanks!
 
Physics news on Phys.org
Marcus95 said:
The voltage between the two conductors is by Gauss's law:$$
V = \int \boldsymbol{E} \cdot d\boldsymbol{r} = E_0 ln(b/a)$$
This equation doesn't make sense. The left side is in volts, the right side is in volts/meter. Check your derivation.
 
  • Like
Likes   Reactions: Marcus95
kuruman said:
This equation doesn't make sense. The left side is in volts, the right side is in volts/meter. Check your derivation.
Thank you, I got it!
 
kuruman said:
This equation doesn't make sense. The left side is in volts, the right side is in volts/meter. Check your derivation.
I had my doubts about this step but for another reason. There is vector potential ##A## inside coaxial cable, so it is
##E=\nabla V+\frac{\partial A}{\partial t}##

so that
##V=\int Edr## doesn't hold (because it is equivalent to ##E=\nabla V##.
Do we make the approximation ##A\approx 0 ##?
 
It's not necessary to invoke the magnetic potential.

You want to use Gauss's theorem to relate E field to potential difference between the conductors. So first you want to determine the geometry of the cable, i.e. the inner and outer radii. Is there a relation between these radii and Z0?

Then: use Gauss's theorem relating the E field to the potential difference V and the geometry and compute the max. allowable V for the given max. E.

Don't forget they want the rms power figure (I think - wording is not clear to me). Also assume an ideal matched line.
 
rude man said:
It's not necessary to invoke the magnetic potential. Then: use Gauss's theorem relating the E field to the potential difference V and the geometry and compute the max. allowable V for the given max. E.

Don't forget they want the rms power figure (I think - wording is not clear to me). Also assume an ideal matched line.
Can you show how you find V using Gauss's theorem(have to solve Poisson's equation?) without using that ##V=\int Edr## because that last integral becomes path dependent when there is vector potential.
 
Delta² said:
Can you show how you find V using Gauss's theorem(have to solve Poisson's equation?) without using that ##V=\int Edr## because that last integral becomes path dependent when there is vector potential.
Delta² said:
Can you show how you find V using Gauss's theorem(have to solve Poisson's equation?) without using that ##V=\int Edr## because that last integral becomes path dependent when there is vector potential.

We are dealing solely with electric, not magnetic, fields. I have never run into a vector potential such that E = ∇ x Ae the way we write H = ∇ x A (or sometimes B = ∇ x A). The former is in fact impossible if there is charge present since ∇⋅E = ρ, not zero, so no vector potential can exist. In any case, forget all vector potentials.

You can relate V to E by solving Laplace's equation for the space between the conductors but you'd still need to do step 1 below. It would in fact be good to do so as a check if you went with my suggestion which is:

(1) Find the outer radius of said space; (2) relate E(r) to V, the potential between the conductors using Gauss; (3) find where E is the largest, then you can determine the max. allowable V given the max allowable E.

To do step 1 you will need one item of data given to you.
 
Last edited:
Actually, solving Laplace's equation is the more direct route. Use the cylindrical coordinate expression ∇2V = (1/r) d/dr (r dV/dr) = 0 since there are no derivatives with respect to θ or z.

But again, your first task is to find the outer radius of the space between the conductors.
 
  • Like
Likes   Reactions: Delta2

Similar threads

Replies
10
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 32 ·
2
Replies
32
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
15K
  • · Replies 6 ·
Replies
6
Views
11K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
9
Views
3K
  • · Replies 3 ·
Replies
3
Views
5K